POH = - log [ OH-]
pOH = - log [ 1 x 10⁻¹²]
pOH = 12
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The experimental mole ratio of silver chloride to barium chloride is calculated as below
fin the mole of each compound
mole= mass/molar mass
moles of AgCl = 14.5g/142.5 g/mol = 0.102 moles of AgCl
moles of BaCl2 = 10.2 g/208 g/mol = 0.049 moles of BaCl2
find the mole ratio by dividing each mole with the smallest mole(0.049)
AgCl= 0.102/0.049 =2
BaCl2 = 0.049/0.049 =1
therefore the mole ratio AgCl to BaCl2 is 2 :1
Answer:
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Explanation:
Electrolysis of acidified water
Water is a poor conductor of electricity, but it does contain some hydrogen ions , H +, and hydroxide ions, OH -. These ions are formed when a small proportion of water molecules naturally dissociate . ... H + ions are attracted to the cathode , gain electrons and form hydrogen gas.
Answer:
2.15 L
Explanation:
M(NaOCl) = 23.0 + 16.0 + 35.5 = 74.5 g/mol
120.3 g *1 mol/74.5 g = 1.615 mol NaOCl
0.750 M = 0.750 mol/L
1.615 mol * 1L/0.750 mol = 2.15 L