You need to use the ideal gas law (PV=nRT) and solve for n. ((3.50atm•10.0L)/(0.0821(L•atm/mol•K)•304K) = n = 1.40 moles. 1 mole of Cl2 = 70.9 gm/mole. The mass would be 99.43 gm
Answer:
adding silver ions , adding chloride ions, removing chloride ions and removing silver chloride.
Explanation:
Barium sulfate is an insoluble ionic compound since it is insoluble in water.
We can differentiate barium ions and sulfate ions away from the surface if we add a small amount of solid barium sulfate is mixed with water and shaken.
The action would shift this reaction away from solid barium sulfate and toward the dissolved ions are adding silver ions , adding chloride ions, removing chloride ions and removing silver chloride.
An ionic and covalent quality has in every molecular bond.
In barium sulfate barium has lowest electronegativities.
Oxygen has highest electronegativities.
so the bond between both barium and sulfate is ionic in character.
Answer: W + BgCz2 arrow WCz + Bg
2 W + BgCz2 arrow 2 WCz + Bg
Explanation:
Cz has 2 so you balcne the other side of WCz.
Since you Balcanes the Cz you changed the W and you Balcanes the other W on the left side.
I will have to say that this statement is true
Answer:
There are 6.022x10^23 molecules
