Answer:
0.3mol C8H18
Explanation:
For this we must first look at the reaction taking place:
C8H18+O2 --> H2O + CO2
Balancing the equation we get:
2(C8H18)+25(O2) --> 18(H2O) + 16(CO2)
Form there we now need to know how many moles of Octane are needed to produce 2.4moles of H2O. The conversion is as follows:
2.4molH2O ((2mol of C8H18)/(18mol of H2O)) = 0.3mol C8H18
3 Primary Consumers: Grasshopper, Praying Mantis, Mouse
3 Secondary Consumers: Hawk, Raccoon, Snake
By the Way: This is Biology, not chemistry
Answer: Payback time = 0.0075
Explanation: Since payback time is calculated as:
payback time = 
First determine the installation cost:
100 mm thick insulation covers 8.3 m². Then 300 mm covers 24.9 m².
To cover 8.3m² costs £20. Then, the cost to cover 24.9 m² is:
cost = 
cost = £60
The cost of putting the insulation is £120, so the total cost is:
total cost = £60 + £120
total cost = £180
Savings per year per 100 mm thick is £80. For 300 mm, the value of annual savings is:
savings = 
savings = 240
payback time =
payback time = 
payback time = 0.75
When 12 moles of O₂ (g) react with C₃H₈O (g) then 8 moles of CO₂ (g) is produced. This is the chemical combustion reaction of propanol producing vapor of CO₂.
<h3>How to calculate the amount of CO₂ produced?</h3>
Alcohols undergo combustion reaction in the presence of oxygen gas to produce vapor of CO₂ and water.
In the given equation,
2 C₃H₈O (g) + 9 O₂ (g) → 6 CO₂ (g) + 8 H₂O (g)
To calculate the number of moles of CO₂ produced, first we have to balance the equation:
Divide the equation by 2
C₃H₈O (g) + 9/2 O₂ (g) → 3 CO₂ (g) + 4 H₂O (g)
Calculate the number of moles of CO₂ (g) produced with 1 mol of O₂ (g)
9/2 O₂ (g) → 3 CO₂ (g)
1 O₂ (g) → 3÷9/2 CO₂ (g) = 0.66 mol CO₂ (g)
For 12 mol of O₂ (g),
12 × 0.66 = 8 mol CO₂ (g)
Therefore, 8 mol of CO₂ (g) is produced from 12 mol of O₂ (g).
Learn more about Combustion reaction here:
brainly.com/question/14335621
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This is a characteristic of a Thermosetting polymer.
