Question

A straight line passing via (2,5) and (26/3,0) where should it intersect the x axis and the y axis

Answer 1

Answer:

( 2  ,  5  )  and   ( 26 /3  ,  0 )

Step-by-step explanation:

Find the equation using the two points.

Use  y = m x + b  to calculate the equation of the line, where  m  represents the slope and  b  represents the y-intercept. To calculate the equation of the line, use the  y = m x + b  format.

Slope is equal to the change in  y  over the change in  x , or rise over run.

The change in  x  is equal to the difference in x-coordinates (also called run), and the change in  y  is equal to the difference in y-coordinates (also called rise).

$m=\frac{y_{2-y_{1} } }{x_{2-y_{1} } }$

Substitute in the values of  x  and  y  into the equation to find the slope.

$m=\frac{0-(5)}{\frac{2}{6} -(2)}$

Multiply the numerator and denominator of the complex fraction by  3 .

Finding the slope  m .

$m=-\frac{3}{4}$

Find the value of  b  using the formula for the equation of a line.

$b=\frac{13}{2}$

Find the x-intercepts.

To find the x-intercept(s), substitute in  0  for  y  and solve for  x .

$0=-\frac{3}{4}x+\frac{13}{2}$

solve the equation

$x=\frac{26}{3}$

x-intercept(s):  $(\frac{26}{3},0)$

Find the y-intercepts.

To find the y-intercept(s), substitute in  0  for  x  and solve for  y .

$0=-\frac{3}{4}*0+\frac{13}{2}$

$y=\frac{13}{2}$

y-intercept(s): $(0,\frac{13}{2})$