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GrogVix [38]
3 years ago
8

Given the graph below and the equation y = 4x, determine which function has the greatest rate of growth?

Mathematics
1 answer:
Ronch [10]3 years ago
8 0

Answer:

Step-by-step explanation:

The equation has a slope of 4

The graph has a slope of 1

The equation has a greater rate of growth.

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Select the correct answer.
Irina18 [472]
D. About 122 units I just took the test
4 0
2 years ago
Linda left home and drove for 2 hours. She stopped for lunch then drove for another 3 hours at a rate that is 10 mph higher than
Verdich [7]

Answer:

44 mph

Step-by-step explanation:

Given that:

Before lunch :

Time taken = 2hrs ; at speed = x mph

After lunch :

Time taken = 3hrs ; at speed = x + 10 mph

Total distance covered = 250 miles :

Distance = speed * time

(2 * x) + (3 * (x + 10)) = 250

2x + 3x + 30 = 250

5x + 30 = 250

5x = 250 - 30

5x = 220

x = 220/ 5

x = 44 mph

Rate before lunch is 44mph

6 0
3 years ago
28.74% of 676.87 to 2 decimal places pls help
gregori [183]

Answer:

the answer of this question is = 194.53

8 0
3 years ago
Which of the following theorems verifies that ABC ~ STU?
Lunna [17]

Answer:

B. AA

Step-by-step explanation:

The diagram given shows that two angles in ∆ABC are congruent to two corresponding angles in ∆STU.

Invariably, the third unknown angle of both triangles would also be equal going by the third angle theorem.

Thus, based on the AA Similarity Theorem which says that two triangles are similar to each other if two corresponding angles of one is congruent to two angles in the other, ∆ABC ~ ∆STU.

4 0
3 years ago
Find the area of following figure...?​
MrRa [10]

Answer:

33600 m²

Step-by-step explanation:

The top and bottom horizontal sides are parallel, so this is a trapezoid with bases DC and AB. The height is BC.

area of trapezoid = (a + b)h/2

where a and b are the lengths of the bases, and h is the height.

We need to find the height, BC.

Drop a perpendicular from point A to segment DC. Call the point of intersection E. E is a point on segment DC.

DE + EC = DC

EC = AB = 360 m

DC = 600 m

DE + 360 m = 600 m

DE = 240 m

Use right triangle ADE to find AE. Then BC = AE.

DE² + AE² = AD²

DE² + 240² = 250²

DE² = 62500 - 57600

DE² = 4900

DE = √4900

DE = 70

BC = 70 = h

area = (a + b)h/2

area = (600 m + 360 m)(70 m)/2

area = 33600 m²

4 0
1 year ago
Read 2 more answers
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