Answer:
D(- 2, 9 )
Step-by-step explanation:
Under a reflection in the y- axis
a pont (x, y ) → (- x, y )
Given D'(2, 9 ) is the image of D, then
D(- 2, 9 ) ← are the original coordinates
Since D(- 2, 9 ) → D'(2, 9 )
let's firstly convert the mixed fractions to improper fractions and then add, bearing in mind that the LCD from 8 and 4 is simply 8.
![\bf \stackrel{mixed}{5\frac{7}{8}}\implies \cfrac{5\cdot 8+7}{8}\implies \stackrel{improper}{\cfrac{47}{8}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{47}{8}+\cfrac{11}{4}\implies \stackrel{\textit{using the LCD of 8}}{\cfrac{(1)47~~-~~(2)11}{8}}\implies \cfrac{47-22}{8}\implies \cfrac{25}{8}\implies 3\frac{1}{8}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bmixed%7D%7B5%5Cfrac%7B7%7D%7B8%7D%7D%5Cimplies%20%5Ccfrac%7B5%5Ccdot%208%2B7%7D%7B8%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B47%7D%7B8%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ccfrac%7B47%7D%7B8%7D%2B%5Ccfrac%7B11%7D%7B4%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Busing%20the%20LCD%20of%208%7D%7D%7B%5Ccfrac%7B%281%2947~~-~~%282%2911%7D%7B8%7D%7D%5Cimplies%20%5Ccfrac%7B47-22%7D%7B8%7D%5Cimplies%20%5Ccfrac%7B25%7D%7B8%7D%5Cimplies%203%5Cfrac%7B1%7D%7B8%7D)
Answer:
-4/3
Step-by-step explanation:
3 5/9= 32/9 and -2 2/3=-8/3 So, 32/9 * -3/8=-4/3 :)
Answer:
cos(a + b) = 
Step-by-step explanation:
cos(a + b) = cos(a).cos(b) - sin(a).sin(b) [Identity]
cos(a) = 
cos(b) = 
Since, terminal side of angle 'a' lies in quadrant 3, sine of angle 'a' will be negative.
sin(a) =
[Since, sin(a) =
]
= 
= 
Similarly, terminal side of angle 'b' lies in quadrant 2, sine of angle 'b' will be negative.
sin(b) =
= 
= 
By substituting these values in the identity,
cos(a + b) = 
= 
= 
= 
Therefore, cos(a + b) = 
Answer:
Step-by-step explanation:
h=11.4 in
r=5.1 in
v=3.14*r^2*(h/3)
V=3.14*5.1^2*(11.4/3)=3.14*26.01*3.8=310.35