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SOVA2 [1]
3 years ago
5

in a box of chocolates, 1/5 of the chocolates contain nuts. the rest of the chocolates do not contain nuts. write down the ratio

of the number of chocolates that contain nuts to the number of chocolates that do not contain nuts. give your answer in the form 1:n
Mathematics
1 answer:
valina [46]3 years ago
4 0

Answer:

The ratio of the number of chocolates that contain nuts to the number of chocolates = 1:4

Step-by-step explanation:

The parameters given are;

Proportion of the box of chocolates that contain nuts = 1/5

Proportion of the box of chocolates that do not contain nuts = 1 - 1/5 = 4/5

Therefore, we have in a box of chocolates with five chocolates;

The number of chocolates that contain nuts = 1

The number of chocolates that do not contain nuts = 4

Which gives the ratio of the number of chocolates that contain nuts to the number of chocolates as 1:4.

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I hope this helps you



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In a quiz-based program, there are three teams A, B and C. There is a total of five rounds in a game; 20 marks are given for eac
9966 [12]

From the given scenarios, the positions of winning of each team is; Team C came first, Team A came second and Team B came third

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From the question, we can derive the following;

Marks gained by team A = 3 × 20 = 60 marks

Marks deducted = 2 × 10 = 20 marks

Hence;

Total marks for Team A = 60 - 20 = 40 marks

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Hence, total marks of team B = 40 - 20 = 20 marks

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Marks deducted = 1 × 10 = 10 marks

Hence,  total marks of team C = 60 - 10 = 50 marks

Thus, we can conclude that;

Team C came first, Team A came second and Team B came third

Read more about Probability of winning at; brainly.com/question/24756209

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7 0
2 years ago
During one waiter’s shift, he delivered 13 appetizers, 17 entrées, and 10 desserts.
Romashka-Z-Leto [24]

Answer:

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Step-by-step explanation:

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lukranit [14]
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