Answer:
X=30
Step-by-step explanation:
...
Answer:
see below
Step-by-step explanation:
(ab)^n=a^n * b^n
We need to show that it is true for n=1
assuming that it is true for n = k;
(ab)^n=a^n * b^n
( ab) ^1 = a^1 * b^1
ab = a * b
ab = ab
Then we need to show that it is true for n = ( k+1)
or (ab)^(k+1)=a^( k+1) * b^( k+1)
Starting with
(ab)^k=a^k * b^k given
Multiply each side by ab
ab * (ab)^k= ab *a^k * b^k
( ab) ^ ( k+1) = a^ ( k+1) b^ (k+1)
Therefore, the rule is true for every natural number n
That's 4! (faculty), ie., 4x3x2x1 = 24.
one of four can win, then there are 3 left for second place, and so on...
Your answer will be the third option.
Sequence: -4, 8, -16
rate of increase: -16/8 = -2
If you make A1 the first term in the sequence you must use (n-1) in the explicit formula. If you go backwards in the sequence to find A0 = 2 then you would use n.
The don't have A0 = 2 listed as an option so we use A1 = -4 and (n-1) terms.
An = -4(-2)^(n-1)
Solving for the 5th term A5, use n = 5
A5 = -4(-2)^(5-1)
A5 = -4(16)
A5 = -64
So the answer is B.
