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3 years ago

A. How high above the water is the roadway in meters? Round to the nearest hundredth. (199 ft)

1 answer:

6 0

A.
1 meter = 3.28 feet
Height = 199 / 3.28
Height = 60.6707 m
To the nearest hundredth = 60.67 m

B.
1 Kilometer = 1000 meter
1 meter = 3.28084 feet
1 kilometer = 3280.84 feet
Length = 26,372 / 3280.84
Length = 8.0382 km
To the nearest hundredth = 8.04 km<span />

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Line m is represented by the equation below. Select all equation that represent lines perpendicular to line m.

Korvikt [17]

Answer:

y = -2/3x + 4

y+1 = -4/6(x + 5)

Step-by-step explanation:

y = -2/3x + 4

y+1 = -4/6(x + 5) *-4/6 is equal to -2/3

perpendicular lines have slope that are opposite signs and reciprocals

the slope of the original line in this problem is 3/2 so any line with a slope of -2/3 is perpendicular to it

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3 years ago

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Find the counterclockwise circulation and outward flux of the field Fequals7 xy Bold i plus 2 y squared Bold j around and over t

77julia77 [94]

Answer:

The counterclockwise circulation is $\frac{7}{12}$ and the outward flux is $\frac{11}{15}$

Step-by-step explanation:

We are given the field $F(x,y) = (7xy,2y^2)$ . A picture of the region and the path we are considering is attached. Recalll the following theorems.

Given a field of the form F(x,y)=(f(x,y),g(x,y) with f,g having continous partial derivates, C is a closed path counterclockwise oriented, R is the region enclosed by C and n is the normal vector pointing outwards of the path C. Then

$\oint_C F\cdot dr =\iint_R \frac{\partial f}{dy}- \frac{\partial g}{dx} dA$ (this one calculates the counterclockwise circulation)

$\oint_C F\cdot n ds =\iint_R (\frac{\partial f}{dx}+ \frac{\partial g}{dy} dA$ (This one calculates the outward flux)

Then, recall that in our case f(x,y) = 7xy, g(x,y)=2y^2[/tex]. Then

$\frac{\partial f}{dx} = 7y,\frac{\partial f}{dy} = 7x$

$\frac{\partial g}{dx}=0, \frac{\partial g}{dy} = 4y$ .

Note that we just need to describe our region R. The region R lies between the parabola y=x^2 and the line y=x. Thus, one way to describe the region is as follows $0\leq x \leq 1, x^2\leq y \leq x$ . Then, using the previous results, we get that

$\oint_C F\cdot dr =\int_{0}^{1}\int_{x^2}^{x}7x-0dydx = 7\int_{0}^1x(x-x^2)dx = 7 \left.(\frac{x^3}{3}-\frac{x^4}{4})\right|_{0}^1 = 7(\frac{1}{3}-\frac{1}{4}) = \frac{7}{12}$ (circulation)

$\oint_C F\cdot n ds=\int_{0}^{1}\int_{x^2}^{x}7y+4ydydx = \frac{11}{2}\int_{0}^1\left.y^2\right_{x^2}^{x}dx = \frac{11}{2}\int_{0}^{1}x^2-x^4 dx = \frac{11}{2}\left(\frac{x^3}{3}-\frac{x^5}{5})\right|_{0}^{1}=\frac{11}{2}(\frac{1}{3}-\frac{1}{5})=\frac{11}{15}$ (flux)

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3 years ago

Mr. Yu applies 12 ounce of fertilizer to every 58 square meter of his lawn.How many ounces of fertilizer does Mr. Yu use per squ

DedPeter [7]

1/2 divided by 5/8
Keep Change Flip=

1/2 x 8/5= 0.8
0.8 = 8/10 simpified 4/5

Answer: 4/5

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3 years ago

A bike rental company charges a $5 service fee and $1 per hour. If this situation is represented as a function, what would be th

Elenna [48]

Write as a function equation: where f(x) is the same as "y"

f(x) = 5 + 1x ------ y = 1x + 5

Use: y = mx + b (Where m = slope and b is y intercept)

Slope is 1 and y intercept is +5

Remember slope is rise over run so 1 can be written as 1 / 1 and interpreted as rise 1 and run 1 both in the positive direction.

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3 years ago

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What do you round 19 and 43 minutes

Leviafan [203]

You could round it to 20 and 45 maybe

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