Answer:
1. y = 4
2. x = 10
3. n = 6
4. m = 4
5. h = 2
Step-by-step explanation:
Hope this helps!!
Answer: 1,365 possible special pizzas
Step-by-step explanation:
For the first topping, there are 15 possibilities, for the second topping, there are 14 possibilities, for the third topping, there are 13 possibilities, and for the fourth topping, there are 12 possibilities. This is how you find the number of possible ways.
15 * 14 * 13 * 12 = 32,760
Now, you need to divide that by the number of toppings you are allowed to add each time you add a topping.
4 * 3 * 2 * 1 = 24
32,760 / 24 = 1,365
There are 1,365 possible special pizzas
Answer:
1. 
2. 
3. 
4. ![40^{\frac{2}{3}}=4\sqrt[3]{25} =4325](https://tex.z-dn.net/?f=40%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%3D4%5Csqrt%5B3%5D%7B25%7D%20%3D4325)
5. Step 4: 
6. 
Step-by-step explanation:
Use the following properties:
![a^{\frac{x}{y} } =\sqrt[x]{a^{y} }](https://tex.z-dn.net/?f=a%5E%7B%5Cfrac%7Bx%7D%7By%7D%20%7D%20%3D%5Csqrt%5Bx%5D%7Ba%5E%7By%7D%20%7D)
![\sqrt[n]{ab} =\sqrt[n]{a} \sqrt[n]{b}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bab%7D%20%3D%5Csqrt%5Bn%5D%7Ba%7D%20%5Csqrt%5Bn%5D%7Bb%7D)




So:
1. ![27^{\frac{2}{3} } =\sqrt[3]{27^{2}} =\sqrt[3]{729} }=9](https://tex.z-dn.net/?f=27%5E%7B%5Cfrac%7B2%7D%7B3%7D%20%7D%20%3D%5Csqrt%5B3%5D%7B27%5E%7B2%7D%7D%20%3D%5Csqrt%5B3%5D%7B729%7D%20%7D%3D9)
2. 
3. ![(-243)^{\frac{3}{5} } =\sqrt[5]{-243^{3} } =\sqrt[5]{-14348907} =-27](https://tex.z-dn.net/?f=%28-243%29%5E%7B%5Cfrac%7B3%7D%7B5%7D%20%7D%20%3D%5Csqrt%5B5%5D%7B-243%5E%7B3%7D%20%7D%20%3D%5Csqrt%5B5%5D%7B-14348907%7D%20%3D-27)
4. ![40^{\frac{2}{3}}=\sqrt[3]{40^{2} } =\sqrt[3]{2^{6} 5^{2} } =\sqrt[3]{2^{6} } \sqrt[3]{5^{2} } =2^{\frac{6}{3} } 5^{\frac{2}{3} } =4 *5^{\frac{2}{3} } =4\sqrt[3]{5^{2} } =4\sqrt[3]{25}=4325](https://tex.z-dn.net/?f=40%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%3D%5Csqrt%5B3%5D%7B40%5E%7B2%7D%20%7D%20%3D%5Csqrt%5B3%5D%7B2%5E%7B6%7D%205%5E%7B2%7D%20%7D%20%3D%5Csqrt%5B3%5D%7B2%5E%7B6%7D%20%7D%20%5Csqrt%5B3%5D%7B5%5E%7B2%7D%20%7D%20%3D2%5E%7B%5Cfrac%7B6%7D%7B3%7D%20%7D%205%5E%7B%5Cfrac%7B2%7D%7B3%7D%20%7D%20%3D4%20%2A5%5E%7B%5Cfrac%7B2%7D%7B3%7D%20%7D%20%3D4%5Csqrt%5B3%5D%7B5%5E%7B2%7D%20%7D%20%3D4%5Csqrt%5B3%5D%7B25%7D%3D4325)
5. 
6.
![(-8c^{9} d^{-3} )^{\frac{1}{3} } *(6c^{-1}d^{4})^{2} =\sqrt[3]{-8} c^{3} d^{-1} 36c^{-2} d^{8} \\\\-2c^{3} d^{-1} 36c^{-2} d^{8}=-72cd^{7}](https://tex.z-dn.net/?f=%28-8c%5E%7B9%7D%20d%5E%7B-3%7D%20%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%20%7D%20%2A%286c%5E%7B-1%7Dd%5E%7B4%7D%29%5E%7B2%7D%20%3D%5Csqrt%5B3%5D%7B-8%7D%20c%5E%7B3%7D%20d%5E%7B-1%7D%2036c%5E%7B-2%7D%20d%5E%7B8%7D%20%5C%5C%5C%5C-2c%5E%7B3%7D%20d%5E%7B-1%7D%2036c%5E%7B-2%7D%20d%5E%7B8%7D%3D-72cd%5E%7B7%7D)
Given, the density of a particular brand of gasoline = 0.737 g/ml.
13.4 gallon of tank given. We have to find the mass of gasoline to fill the tank.
First we will convert 13.4 gallon to ml.
We know that 1 gallon = 3.78541 litre
And 1 litre = 1000 ml
So we can write 1 gallon =
= 3785.41 ml.
13.4 gallon =
ml = 50724.494 ml.
Let's take there is x grams of gasoline
We know that density = (mass/ volume) = 
So we can write,

To find x we will multiply both sides by 50724.494. we will get,



So we have got the required answer.
Mass of gasoline = 37383.95 grams.