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Lynna [10]
3 years ago
6

A. How high above the water is the roadway in meters? Round to the nearest hundredth. (199 ft)

Mathematics
1 answer:
xxMikexx [17]3 years ago
6 0
A.
1 meter = 3.28 feet
Height = 199 / 3.28
Height = 60.6707 m
To the nearest hundredth = 60.67 m

B.
1 Kilometer = 1000 meter
1 meter = 3.28084 feet
1 kilometer = 3280.84 feet
Length = 26,372 / 3280.84
Length = 8.0382 km
To the nearest hundredth = 8.04 km<span />
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I need these done as quick as possible and i have no clue what to do.
Korvikt [17]

Answer:

1. y = 4

2. x = 10

3. n = 6

4. m = 4

5. h = 2

Step-by-step explanation:

Hope this helps!!

3 0
3 years ago
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A restaurant offers a special pizza with any 4 toppings. If the restaurant has 15 topping from which to choose, how many differe
OlgaM077 [116]

Answer: 1,365 possible special pizzas

Step-by-step explanation:

For the first topping, there are 15 possibilities, for the second topping, there are 14 possibilities, for the third topping, there are 13 possibilities, and for the fourth topping, there are 12 possibilities. This is how you find the number of possible ways.

15 * 14 * 13 * 12 = 32,760

Now, you need to divide that by the number of toppings you are allowed to add each time you add a topping.

4 * 3 * 2 * 1 = 24

32,760 / 24 = 1,365

There are 1,365 possible special pizzas

8 0
3 years ago
A temperature record in Antarctica was -120.the temperature recorded in the Sahara desert was 129.how many degrees warmer is 129
DanielleElmas [232]

This is   129 - (-120)

= 129 + 120

= 249  degrees warmer

7 0
3 years ago
Plz write this on paper help me and send it❤️
vovangra [49]

Answer:

1. 27^{\frac{2}{3} } =9

2. \sqrt{36^{3} } =216

3. (-243)^{\frac{3}{5} } =-27

4. 40^{\frac{2}{3}}=4\sqrt[3]{25} =4325

5. Step 4: (\frac{343}{27}) ^{-1} =\frac{27}{343}

6. D. -72cd^{7}

Step-by-step explanation:

Use the following properties:

a^{\frac{x}{y} } =\sqrt[x]{a^{y} }

\sqrt[n]{ab} =\sqrt[n]{a} \sqrt[n]{b}

a^{-n} =\frac{1}{a^{n} }

(xy)^{z} =x^{z} y^{z} \\\\

(x^{y}) ^{z} =x^{yz}

x^{y} x^{z} =x^{y+z}

So:

1. 27^{\frac{2}{3} } =\sqrt[3]{27^{2}} =\sqrt[3]{729} }=9

2. \sqrt{36^{3} } =\sqrt{36*36*36} =\sqrt{36} \sqrt{36}  \sqrt{36} =6*6*6=216

3. (-243)^{\frac{3}{5} } =\sqrt[5]{-243^{3} } =\sqrt[5]{-14348907} =-27

4. 40^{\frac{2}{3}}=\sqrt[3]{40^{2} } =\sqrt[3]{2^{6} 5^{2} } =\sqrt[3]{2^{6} } \sqrt[3]{5^{2} } =2^{\frac{6}{3} } 5^{\frac{2}{3} } =4 *5^{\frac{2}{3} } =4\sqrt[3]{5^{2} } =4\sqrt[3]{25}=4325

5. (\frac{343}{27}) ^{-1} =\frac{1}{\frac{343}{27} } =\frac{27}{343}

6.

(-8c^{9} d^{-3} )^{\frac{1}{3} } *(6c^{-1}d^{4})^{2} =\sqrt[3]{-8} c^{3} d^{-1} 36c^{-2} d^{8} \\\\-2c^{3} d^{-1} 36c^{-2} d^{8}=-72cd^{7}

7 0
3 years ago
A particular brand of gasoline has a density of 0.737 g/ml at 25 ∘c. how many grams of this gasoline would fill a 13.4 gal tank
ruslelena [56]

Given, the density of a particular brand of gasoline = 0.737 g/ml.

13.4 gallon of tank given. We have to find the mass of gasoline to fill the tank.

First we will convert 13.4 gallon to ml.

We know that 1 gallon = 3.78541 litre

And 1 litre = 1000 ml

So we can write 1 gallon = (3.78541)(1000) ml = 3785.41 ml.

13.4 gallon = (3785.41)(13.4) ml = 50724.494 ml.

Let's take there is x grams of gasoline

We know that density = (mass/ volume) = \frac{x}{50724.494}

So we can write,

0.737 =\frac{x}{50724.494}

To find x we will multiply both sides by 50724.494. we will get,

(0.737)(50724.494) =(\frac{x}{50724.494}) (50724.494)

(0.737)(50724.494) = x

37383.95 = x

So we have got the required answer.

Mass of gasoline = 37383.95 grams.

5 0
3 years ago
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