Answer:
Kindly check explanation
Step-by-step explanation:
Given the following :
P(rain) = p(R) = 30% = 0.3
P(being late Given that it rains) = P(late | rain) = p(L|R) = 0.4
P(being late Given no rain) = P(late | no rain) = 0.15
(a) What is the probability that it will rain and the bus will be late? = P(RAINnLate) = P(RnL)
P(RnL) = p(R) * p(L|R)
P(RnL) = 0.3 * 0.4
= 0.12
(b) What is the probability that the bus will be late?
P(L) = p(R) * p(L|R) + p(no rain) * p(late | no rain)
P(L) = (0.3 * 0.4) + (1 - 0.3)*(0.15)
P(L) = 0.12 + 0.105
P(L) = 0.225
(c) Given that the bus ran late, what was the probability that it was not raining?
Given that bus ran late, the probability that it was not raining = p(no rain | Late)
p(no rain | Late) = 1 - p(R | L)
Recall :
P(RnL) = p(L) * p(R|L)
0.12 = 0.225 * p(R|L)
p(R|L) = 0.12 / 0.225
p(R|L) = 0.5333
p(no rain | Late) = 1 - 0.533
= 0.46666
= 0.467
They are always on a coplanar
Answer: I would think it would be 5x-1 and 3x+5,
I may be wrong i'm only in 8th grade >.>
The total numbers of sections are 16.
Step-by-step explanation:
Given:
Number of boys in school = 576
Number of girls in school = 448
To find: Total Number of sections such that each section has either boys or girls.
Height Common Factor ( HCF ) of both number gives the number of students in a section.
HCF of 576 and 448
576 = 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3
448 = 2 × 2 × 2 × 2 × 2 × 2 × 7
HCF = 2 × 2 × 2 × 2 × 2 × 2 = 64
Number of sections of Boys = 576/64 = 9
Number of sections of girls 448/64 = 7
Total Number of sections = 9 + 7 = 16
Therefore, The total numbers of sections are 16.
