Answer:
BIL is the answer to that one day
You basically have to count how many days received the amount of mail listed in the left column. Then out of the total amount of mail received, you would compute the fraction of the days during which a given amount of mail was received.
For instance, on every day, at least 5 pieces of mail were counted, so there are 0 days on which 0-4 pieces of mail were received.
On the other hand, on days 5-7 (15, 18, 19), the amount of mail received fell within the 15-19 range. This means out of 7 days, 15-19 pieces of mail were received on 3 of those days. So the frequency with which this occurred was
.
So what you should get in the right column is
Answer:
All speed from 0 mi/h and 11 mi/h were reached because the initial and final speed was 0 mi/h the speed of 10 mi/hr was reached at least twice in the race.
Step-by-step explanation:
Given,
Total distance covered = 6.2 miles,
Time taken = 34 minutes = hours
( 1 hour = 60 minutes )
Since,
Thus, the speed of the runner =
= 10.9411764706
≈ 11 miles per hour
Thus, the average speed of the runner is 11 miles per hour ( approx )
By MVT,
The speed was exactly 10 mi/hr at least twice in the race.
By intermediate value theorem,
All speed from 0 mi/h and 11 mi/h were reached because the initial and final speed was 0 mi/h the speed of 10 mi/hr was reached at least twice in the race.
Answer: 27.9 let me know if you need a another answer I hope this helps!