Answer:
A. The distribution of sample means of the differences will be approximately normal if there are at least 30 years of data in the sample and/or if the population of differences in winning times for all years is normal.
Step-by-step explanation:
In other to perform a valid paired test, one of the conditions required is that, data for both groups must be approximately normal. To attain normality, the population distribution for the groups must be normal or based on the central limit theorem, the sample size must be large enough, usually n > 30. Hence, once either of the two conditions are met, the paired sample will be valid.
In calculus, we use derivatives to find the instantaneous rate of change at any point on a graph. To find the average rate of change, we just find the slope of the secant line that intercepts two points on the graph.
We find slope with the following equation:

In this case, we are looking for the slope from x = -1 to x = 1. We have both x values, so next we need the y values.
F(-1) = (-1)^2 - (-1) - 1 = 1
F(1) = (1)^2 - (1) - 1 = -1
Now plug in the x and y values to find the slope:
The answer is -1.
Let's assume
It started in 2000
so, t=0 in 2000

we can use formula

we can plug value

In 2005, the same survey was made and the total amount of gamma ray bursts was 7.3 million
so, at t=2005-2000=5
P(t)=7.3 million
we can plug value and then we can solve for r


now, we can plug back

now, we have
P(t)=1 billion =1000 million
so, we can set it and then we can solve for t


approximately

Year is 2000+192
year is 2192................Answer
f(x) = x² - 8x + 3
y = x² - 8x + 3
- 3 - 3
y - 3 = x² - 8x + 16
y - 3 + 16 = x² - 8x + 16
y + 13 = x² - 8x + 16
y + 13 = (x - 4)²
- 13 - 13
y = (x - 4)² - 13
f(x) = (x - 4)² - 13
For this equation, we can let c = the value of one coupon
<span>4c = 108 - 76 </span>
<span>4c = 32 </span>
<span>c= $8
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