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3 years ago

Plzzz helppp with mathh

Mathematics

2 answers:

Scorpion4ik [409]3 years ago

5 0

Answer:

I believe that it is 2/3

I apologize if that was wrong

Masja [62]3 years ago

3 0

Answer:

Try 1 1/6

Step-by-step explanation:

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50 POINTS:A chess competition has eliminations each round. The table below shows the number of players in each of the first 5 ro

Ket [755]

Round (x) 1 2 3 4 5
Players f(x) 256 128 64 32 16

16-256 / 5 - 1 = -240/4 = -60

A.) −60; on average, there was a loss of 60 each round.

7 0

3 years ago

Solve ? -4-4(-x-1)=-4(6+2x)

soldier1979 [14.2K]

$-4-4(-x-1)=-4(6+2x)\\\\-4+4x+4=-24-8x\\\\4x=-24-8x \ \ /+8x\\\\12x=-24 \ \ /:12\\\\\huge\boxed{x=-2}$

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3 years ago

GIVING BRAINLIEST FOR BEST ANSWER!

Stels [109]

Answer: The answer is 11 1/24 or in decimal form 11.04

Step-by-step explanation:

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2 years ago

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12.41-6.47 use benchmark to estimate

DedPeter [7]

The answer will be 5.94

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3 years ago

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If a person takes a prescribed dose of 10 milligrams of Valium, the amount of Valium in that person's bloodstream at any time ca

aleksandr82 [10.1K]

Answer:

(a)8.0mg

(b)36.87 hours

(c)-0.168

Step-by-step explanation:

The amount of Valium in that person's bloodstream at any time can be modeled with the exponential decay function $A ( t ) = 10 e^{ -0.0188 t$ (t in hours)

(a)After 12 Hours

$A ( 12) = 10 e^{ -0.0188*12}\\=7.98\\\approx 8.0 mg $(to the nearest tenth of a milligram)$

(b)If A(t)=5mg

Then:

$5= 10 e^{ -0.0188 t}\\$Divide both sides by 10\\0.5=e^{ -0.0188 t}\\$Take the natural logarithm of both sides\\ln (0.5)=-0.0188 t\\t=ln (0.5) \div (-0.0188)\\$t=36.87 hours (to two decimal places.)$

(c)

$A ( t ) = 10 e^{ -0.0188 t}\\A'(t)=10(-0.0188)e^{ -0.0188 t}\\A'(t)=-0.188e^{ -0.0188 t}\\$At 6 hours, the rate at which the amount of Valium is decaying therefore is:\\A'(6)=-0.188e^{ -0.0188*6}\\$=-0.168 ( to three decimal places)$

3 0

3 years ago