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vaieri [72.5K]
3 years ago
11

The cost of a computer declined by

Mathematics
2 answers:
slava [35]3 years ago
8 0

Answer:

the answer is 51.75

Step-by-step explanation:

What you do is take 5.75 and multiply it by 9 and that's your answer

EleoNora [17]3 years ago
6 0

Answer:

$51.75

Step-by-step explanation:

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Please help ill give brainliest
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m > 1 :)

Step-by-step explanation:

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4 quarts are in a single gallon
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(6 x 9 = f) f x 16 = b <br><br> what dose b equal
Tcecarenko [31]

Step-by-step explanation:

f=6×9

aubstituting f=6×9

6×9×16=b

864=b

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3 years ago
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Assume that thermometer readings are normally distributed with a mean of degrees and a standard deviation of 1.00degrees C. A th
Andrew [12]

Answer:

0.2684 is the probability that the temperature reading is between 0.50 and 1.75.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 0 degrees

Standard Deviation, σ = 1 degrees

We are given that the distribution of thermometer readings is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(Between 0.50 degrees and 1.75 degrees)

P(0.50 \leq x \leq 1.75)\\\\ = P(\displaystyle\frac{0.50 - 0}{1} \leq z \leq \displaystyle\frac{1.75-0}{1})\\\\ = P(0.50 \leq z \leq 1.75)\\= P(z \leq 1.75) - P(z < 0.50)\\= 0.9599 - 0.6915 = 0.2684 = 26.84\%

0.2684 is the probability that the temperature reading is between 0.50 and 1.75.

7 0
3 years ago
For any circle, which ratio is equal to the number n? Select all that apply. Plsss help me!!
barxatty [35]

Answer:

Options A-C-F

Step-by-step explanation:

we know that

<em>The circumference of a circle is equal to</em>

C=\pi D  or  C=2\pi r

where

D is the diameter and r is the radius

therefore

\pi =\frac{C}{D}  or \pi =\frac{C}{2r}

The number pi is the ratio circumference - diameter or is the ratio circumference - 2 times radius

<em>The area of the circle is equal to</em>

A=\pi r^{2}

therefore

The number pi is the ratio Area - radius squared

6 0
3 years ago
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