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nordsb [41]
4 years ago
7

What wavelength photon would be required to ionize a hydrogen atom in the ground state and give the electron a kinetic energy of

10.7 eV?
Physics
1 answer:
ELEN [110]4 years ago
5 0

Answer:

∝= 51.08 nm

Explanation:

It is necessary that the photon  have the enough energy to get out of the ground state and the energy required to jump out of the ground state = 13.6 eV

so we have the total energy needed:

E= 13.6+10.7

E= 24.3 eV

Planck constant = 6.62*10^-34

with the E formula we could clear the wavelength variable like this....

E= hf

E= h(c/∝)

∝= h*(c/E)

∝=(6.62*10^-34) * [ 3*10^8  /  24.3*(1.6*10^-19)J ]

∝= 5.108*10^-8m

now we just need to convert to a nm distance

∝= 51.08 nm

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How much work is done lifting a 9.10-kg box straight up onto a shelf that is 1.80 m high
love history [14]

P= 10m = 10 x 9.10 = 91 N

Work is done lifting a 9.10-kg box straight up onto a shelf that is 1.80 m high :

A= Ph = 91 x 1.80 = 163.8 J

ok done. Thank to me :>

5 0
3 years ago
Scientists described light as a wave because the results of many experiments with light demonstrated that light behaves as a wav
Ksju [112]

The answer is Data collected from many experiments could not be explained.


Explanation:

With pretty much every science theory, the theory can not change without valid experimentation by multiple professionals.

4 0
3 years ago
Read 2 more answers
1. Although mercury is a metal, it is a liquid at room temperature. Mercury melts at about -39°C. If
grigory [225]

Answer:

I think so because if it starts at a low temperature for that material, it should melt when you bring it up to that temperature.

7 0
3 years ago
The Hi line of the Balmer series is emitted in the transition from n = 3 to n = 2. Compute the wavelength of this line for l H a
irina1246 [14]

Answer:

\lambda=550\ nm

Explanation:

The Hi line of the Balmer series is emitted in the transition from n = 3 to n = 2 i.e. n_i=3 and n_f=2

The wavelength of Hi line of the Balmer series is given by :

\dfrac{1}{\lambda}=R(\dfrac{1}{n_f}-\dfrac{1}{n_i})

\dfrac{1}{\lambda}=1.09\times 10^7\times (\dfrac{1}{2}-\dfrac{1}{3})

\lambda=5.50\times 10^{-7}\ m

\lambda=550\ nm

So, the wavelength for this line is 550 nm. Hence, this is the required solution.

6 0
3 years ago
A grasshopper leaps into the air at a 62° angle above the horizontal, and follows a parabolic arc in free fall after it leaves t
harina [27]

Answer:

d. None of the above.

Explanation:

In a parabolic motion, you have that in the complete trajectory the component velocity is constant and the vertical component changes in time. Then, the total velocity vector is not zero.

In the complete trajectory the gravitational acceleration is always present. Then, the grasshopper's acceleration vector is not zero.

At the top of the arc the grasshopper is not at equilibrium because the gravitational force is constantly acting on the grasshopper.

Then, the correct answer is:

d. None of the above.

5 0
3 years ago
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