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3 years ago

The thermal energy in a hot iron flows into a shirt. what can possibly be said about this situation

2 answers:

7 0

The correct answer for this question would be option A. When the thermal energy in a hot iron flows into a shirt, what we can possibly say about this situation is that, the iron is warmer than the shirt. The transfer of heat from the iron to the shirt is called heat conduction. Hope this answer helps.

bogdanovich [222]3 years ago

3 0

Answer:

a) The hot iron is warmer than the shirt.

Explanation:

Thermal energy always flows from a hot object to a cold object.

This process is similar to water flowing from a higher level to a lower level.

In the given question, since the iron is hot, it has greater thermal energy compared to the shirt. So heat flow is from the hot iron to the shirt.

( like during the ironing of a shirt).

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When the velocity of a mass on a spring is zero, the acceleration is at

Akimi4 [234]

Answer:

A maximum

Explanation:

When displacement is maximum, velocity is Zero and vice versa

When displacement is maximum, acceleration is maximum and when it is zero, acc. Is zero

3 0

3 years ago

A student shakes a rope such that 20 complete vibrations are made in 4.00 seconds. Determine the vibrational frequency of the ro

fgiga [73]

Answer:

The vibrational frequency of the rope is 5 Hz.

Explanation:

Given;

number of complete oscillation of the rope, n = 20

time taken to make the oscillations, t = 4.00 s

The vibrational frequency of the rope is calculated as follows;

$Frequency = \frac{number \ of \ complete \ vibrations}{time \ taken} \\\\Frequency = \frac{20 }{4 \ s} \\\\Frequency = 5 \ Hz$

Therefore, the vibrational frequency of the rope is 5 Hz.

8 0

2 years ago

A 47.2 kg girl is standing on a 177 kg plank. The plank, originally at rest, is free to slide on a frozen lake, which is a flat,

Softa [21]

Answer:

v_g,i = 1.208 m/s

Explanation:

We are given;

Mass of girl; m_g = 47.2 kg

Mass of plank; m_p = 177 kg

Let the velocity of girl to ice be v_g,i

Let the velocity of plank to ice be v_p,i

Since the velocity of the girl is 1.53 m/s relative to the plank, then;

v_g,i + v_p,i = 1.53

From conservation of momentum;

m_g × v_g,i = m_p × v_p,i

Thus;

47.2(v_g,i) = 177(v_p,i)

Dividing both sides by 47.2 gives;

v_g,i = 3.75(v_p,i)

v_pi = (v_g,i)/3.75

Thus, from v_g,i + v_p,i = 1.53, we have;

v_g,i + ((v_g,i)/3.75) = 1.53

v_g,i(1 + 1/3.75) = 1.53

1.267v_g,i = 1.53

v_g,i = 1.53/1.267

v_g,i = 1.208 m/s

5 0

3 years ago

An oscillator consists of a block of mass 0.628 kg connected to a spring. When set into oscillation with amplitude 27 cm, the os

oksian1 [2.3K]

Answer:

T=0.372 s, f=2.7 Hz, w=16.9 rad/s, k=179.2 N/m, v= 8.78 m/s, F= 48.4 N

Explanation:

a.)

Period: It is already given in the question "oscillator repeats its motion every 0.372 s".

So T=0.372 s

frequency= f = 1/ T

f = 1/ 0.372

f=2.7 Hz

c).

Angular frequency= w= 2πf

w= 2*π*2.7

w=16.9 rad/s

Spring Constant:

As w= $\sqrt{k/m}$

⇒w²= k/m

⇒k= m*w²

⇒k= 0.628 * 16.9² N/m

⇒k=179.2 N/m

The mass will have maximum speed when it passes through the mean position.

At mean position

Maximum elastic potential energy = Maximum kinetic energy

1/2 k A² = 1/2 m v² ( A is amplitude of oscillation)

⇒ v= $\sqrt{k A^2/m}$

⇒ v= $\sqrt{179.2 * 0.27/ 0.628}$ \

⇒ v= 8.78 m/s

Maximum force will be exerted on the block when it is at maximum distance.

F= k* A ( A is amplitude of oscillation)

F= 179.2 * 0.27 N

F= 48.4 N

5 0

3 years ago

The electric motor in a toy train requires a voltage of 4.9 v. find the ratio of turns on the primary coil to turns on the secon

enyata [817]

So to solve for this problem, this is computed by the following steps:

Vp / Vs ( = Np / Ns

Where:

Vp = Voltage Primary

Vs = Voltage Secondary

Np = Turn ratio Primary

Ns = Turn ratio Secondary.

So plugging in our values: 
110 / 4.9 = Np / Ns
Np / Ns =22.44, so the answer is 22 coils.

4 0

3 years ago