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Sonja [21]
3 years ago
14

The thermal energy in a hot iron flows into a shirt. what can possibly be said about this situation

Physics
2 answers:
Rainbow [258]3 years ago
7 0
The correct answer for this question would be option A. When the thermal energy in a hot iron flows into a shirt, what we can possibly say about this situation is that, the iron is warmer than the shirt. The transfer of heat from the iron to the shirt is called heat conduction. Hope this answer helps.
bogdanovich [222]3 years ago
3 0

Answer:

a) The hot iron is warmer than the shirt.

Explanation:

Thermal energy always flows from a hot object to a cold object.

This process is similar to water flowing from a higher level to a lower level.

In the given question, since the iron is hot, it has greater thermal energy compared to the shirt. So heat flow is from the hot iron to the shirt.

( like during the ironing of a shirt).

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Does mechanical advantage have units? Explain your answer.
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Answer:

The mechanical advantage of a machine is the ratio of the load (the resistance overcome by a machine) to the effort (the force applied). For an ideal (without friction) mechanism, it is also equal to: There is no unit for mechanical advantages since the unit for both input and output forces cancel out.

Explanation:

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Distinguish between basic and derived units
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Base units are defined units based on specific objects or events in the physical world. Derived units are defined by combining base units.

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2 years ago
If a water wave completes one cycle in 2 seconds, what is
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So if a wave completes one cycle in <em>2 seconds</em>, then that is its period.

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Calculate the critical angle for Zircon which has a refractive index of n = 2*
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3 years ago
n ultraviolet light beam having a wavelength of 130 nm is incident on a molybdenum surface with a work function of 4.2 eV. How f
pashok25 [27]

Answer:

The speed of the electron is 1.371 x 10⁶ m/s.

Explanation:

Given;

wavelength of the ultraviolet light beam, λ = 130 nm = 130 x 10⁻⁹ m

the work function of the molybdenum surface, W₀ = 4.2 eV = 6.728 x 10⁻¹⁹ J

The energy of the incident light is given by;

E = hf

where;

h is Planck's constant = 6.626 x 10⁻³⁴ J/s

f = c / λ

E = \frac{hc}{\lambda} \\\\E = \frac{6.626*10^{-34} *3*10^{8}}{130*10^{-9}} \\\\E = 15.291*10^{-19} \ J

Photo electric effect equation is given by;

E = W₀ + K.E

Where;

K.E is the kinetic energy of the emitted electron

K.E = E - W₀

K.E = 15.291 x 10⁻¹⁹ J - 6.728 x 10⁻¹⁹ J

K.E = 8.563 x 10⁻¹⁹ J

Kinetic energy of the emitted electron is given by;

K.E = ¹/₂mv²

where;

m is mass of the electron = 9.11 x 10⁻³¹ kg

v is the speed of the electron

v = \sqrt{\frac{2K.E}{m} } \\\\v =  \sqrt{\frac{2*8.563*10^{-19}}{9.11*10^{-31}}}\\\\v = 1.371 *10^{6} \ m/s

Therefore, the speed of the electron is 1.371 x 10⁶ m/s.

8 0
3 years ago
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