Question

A ski jumper starts from rest from point A at the top of a hill that is a height h1 above point B at the bottom of the hill. The skier and skis have a combined mass of 80 kg. The skier slides down the hill and then up a ramp and is launched into the air at point C that is a height of 10 m above the ground. The skier reaches point C traveling at 42ms.Find his speed at the bottom of the hill which is 10m below the top.

Answer 1

Answer:

$v_i = 44.3 m/s$

Explanation:

As we know that here no friction force is present on the skier so we can say that total mechanical energy is conserved here

so we will have

$\frac{1}{2}mv_i^2 + mgh_1 = \frac{1}{2}mv_f^2 + mgh_2$

now we will have

$h_1 = 0$

$v_f = 42 m/s$

$h_2 = 10 m$

now we have

$v_i^2 = v_f^2 + 2gh_2$

$v_i^2 = 42^2 + 2(9.8)(10)$

$v_i = 44.3 m/s$