its a gene that you either receive from your mother or father.
<span>a.
</span>The frequency of the dominant allele: ___0.4______
<span>b.
</span>The frequency of the recessive allele: ____0.6_____
<span>c.
</span>The percentage of mice that are homozygous
dominant: __16%_______
<span>d.
</span> The
percentage of mice that are heterozygous: _48%________
<span>e.
</span>The percentage of mice that are homozygous
recessive: __36%_______
Let us assign the dominant allele (that of brown hair) letter R
while
We assign the recessive
allele (that of white hair) letter r
We then note down the
Hardy-Weinburg equation p2 + 2pq + q2 = 1
Brown fur population (p2
+ 2pq) = 64% = 0.64
White fur population (q2) = 36% = 0.36
Then we also remember that the frequencies of both allele
add up to 1 (p + q = 1);
Therefore q = ü.36
= 0.6
P = 1 – q = 1 – 0.6 = 0.4
The heterozygous population will be 2*0.6*0.4 = 0.48 = 48%
Homozygous domain population will therefore be (64% - 48%) =
16%
Sexuality selection?
<span>Sexual selection in birds concerns how birds have evolved a variety of mating behaviors, so this could be your answer.</span>
Answer:
A
Explanation:
the process by which green plants and some other organisms use sunlight to synthesize nutrients from carbon dioxide and water. Photosynthesis in plants generally involves the green pigment chlorophyll and generates oxygen as a by-product.
Answer:
1. Growth on cornmeal agar
2. KOH prep
Explanation:
Cornmeal agar is a nutritional deficient media containing :
- Corn meal 8g / zein 40 g / 100ml
- Agar 4g
- Distilled water 200 ml
- Large , highly refractory, thick walled.
KOH preparation (10 - 30% ) used to destroy keratin, leaves fungal hyphae.
- Can add a chitin-specific stain
- Calcofluor white fluorescent stain increases sensitivity
Hence the organism can easily be identified by these two tests.
