An online merchant sells products that can be classified into the following non-intersecting categories: video games, electronic
s and clothing.In any given week, it is estimated that twice as many video games are sold compared to clothing items. However, the number of electronic items sold would be two-thirds of the number of video games sold, less one-fifth of the number of clothing items sold. A total of five items were independently sold in the past week.What is the probability that the five items consisted of three video games, one electronic item and one clothing item?A. 0.03B. 0.06C. 0.08D. 0.12E. 0.15
1 answer:
Answer:
0.15 ( E )
Step-by-step explanation:
Assuming
video game to be : V
electronics : E
clothing : C
From the content of the question
V = 2c
hence E = 2/3 V - 1/5 C
= 2/3 ( 2c ) - 1/5 c
=
therefore : V = 2c and E = 17c / 15
assuming the number of clothing ( c ) = 15
V = 2*15 = 30 and E = ( 17 *15 ) / 15 = 17
Total number of items sold = V + C + E = 30 + 15 + 17 = 62
from here we can determine the probability that of the five items independently sold that there are 3 video game, 1 electronic item and 1 clothing item
attached below is the remaining part of the solution
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<h2>Given :-</h2>
In □PQRS side PQ∥ side RS. If m∠P = 108degree
and m∠R = 53degree
<h2>To Find :-</h2>m∠Q and m∠S.
<h2>Solution :-</h2>According to angle sum property
P∠Q=180−∠P
∠Q=180−108
For angle S
∠S=180−∠R
∠S=180−53
The rest of the question is the attached figure
========================================
solution:
========
As show in the attached figure
∠M = ∠R = 54.4°
∠N = ∠T = 71.2°
∠O = 180° - (∠M + ∠N) = 180° - (54.4°+71.2°) = 54.4°
∠S = 180° - (∠R + ∠T) = 180° - (54.4°+71.2°) = 54.4°
∠O = ∠S = 36°
∴ Δ MNO is similar to Δ RTS
So, the correct statement:
The triangles each have two given angle measures and one unknown angle measure.
