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3 years ago

15

−15x+4≤109 OR −6x+70>−2

2 answers:

Xelga [282]3 years ago

3 0

$-15x+4\leq109\qquad\text{subtract 4 from both sides}\\\\-15x\leq105\qquad\text{change the signs}\\\\15x\geq-105\qquad\text{divide both sides by 15}\\\\\boxed{x\geq-7}\\or\\-6x+70>-2\qquad\text{subtract 70 from both sides}\\\\-6x>-72\qquad\text{change the signs}\\\\6x$

wlad13 [49]3 years ago

3 0

Answer:

all values of x are solutions

Step-by-step explanation:

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