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SpyIntel [72]
3 years ago
7

The positive two-digit integers x and y have the same digits, but in reverse order. Which of the following must be a factor of x

y
(A) 6
(B) 9
(C) 10
(D) 11
(E) 14
Mathematics
1 answer:
shusha [124]3 years ago
5 0

Answer: (D) 11

Step-by-step explanation:

Let the first digit x composed of ab and the second digit y composed of reversed of ab =ba

The sum of x and y will be

x+y = ab+ ba

x+y= (10.a + b) + (10.b +a)

x+y= 10a+b+10b+a

x+y= 11a+11b

By factorization

x+y= 11(a+b)

Therefore 11 is compulsory factor of x and y

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Beth works 8 2/4 hours drives 1 1/4 hours cook 3/4 hour
ElenaW [278]

Answer:

Step-by-step explanation:

10 2/4

1 1/4 + 3/4= 2

2+8= 10

10+2/4= 10 2/4

6 0
4 years ago
3xy; use x = 2, and y = 2​
frosja888 [35]

3xy

Use the substitution method

(3)(2)(2)

(2)(2)= 4

(4)(3)= 12

Answer: 12

8 0
3 years ago
Read 2 more answers
X + 5y = -27<br> -2x - 5y = 24
Rashid [163]

Answer:

Step-by-step explanation:

x+5y=-27

-2x-5y=24

If the signs are the same u minus if they are different u add

So they are different were gonna add

x+5y=-27

-2x-5y=24

-1=-3

You cant divide it further x=-3

Next were gonna subsitute in any equation

x(-3)+5y=-27

-3+5y=-27

+3 to -27

-7+3=-24

5y=24

24/5=4.8 y=4.8

I hope this helps.

4 0
3 years ago
How many different simple random samples of size 5 cab be obtained from a population whose size is 46
otez555 [7]

Answer:

1370754

Step-by-step explanation:

From what I can see, you are probably studying combinations and permutations at the moment. Since this is a question about how many groups of five can be produced from a sample size of 46, the groups are random and not in order, which may rule for us to use the combination formula.

Once you compute this, this answer is basically saying that 1370754 groups of 5 can be created from a sample size of 46

8 0
4 years ago
Select the correct answer,
Slav-nsk [51]
Give me 8 mins i will answer in the comments
6 0
3 years ago
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