Answer:
10
Step-by-step explanation:
first you need to find the prime factors of the three numbers
ex:
prime factor of 18= 
prime of 24=
there is one 2 and one 3 in common
greatest common multiple 2*3=6
so the greatest common multiple is ten because it is the only one that can divide between all three evenly.

so 10 is your answer
Answer:
232.86
Step-by-step explanation:
134.4
+ 98.46
=232.86
232.86
+232.86
=465.72
Sorry that's all I know po
P1=2.5+2.5+4.75+4.75=14.5 cm
0.5 cm - 1 in
2.5 cm - 5 in
4.75 cm - 9.5 in
P2=5+5+9.5+9.5=29 in
Answer:
see the attachment
Step-by-step explanation:
We assume that the question is interested in the probability that a randomly chosen class is a Friday class with a lab experiment (2/15). That is somewhat different from the probability that a lab experiment is conducted on a Friday (2/3).
Based on our assumption, we want to create a simulation that includes a 1/5 chance of the day being a Friday, along with a 2/3 chance that the class has a lab experiment on whatever day it is.
That simulation can consist of choosing 1 of 5 differently-colored marbles, and rolling a 6-sided die with 2/3 of the numbers being designated as representing a lab-experiment day. (The marble must be replaced and the marbles stirred for the next trial.) For our purpose, we can designate the yellow marble as "Friday", and numbers greater than 2 as "lab-experiment".
The simulation of 70 different choices of a random class is shown in the attachment.
_____
<em>Comment on the question</em>
IMO, the use of <em>70 trials</em> is coincidentally the same number as the first <em>70 days</em> of school. The calendar is deterministic, so there will be exactly 14 Fridays in that period. If, in 70 draws, you get 16 yellow marbles, you cannot say, "the probability of a Friday is 16/70." You need to be very careful to properly state the question you're trying to answer.
Since 1 yard is 3 feet 38 feet is 38/3 yards which is 12 and 2/3 yards