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avanturin [10]
2 years ago
7

If there are 300 seventh graders, and 80% passed the benchmark, how many passed the benchmark

Mathematics
1 answer:
notsponge [240]2 years ago
7 0

Answer:

240 seventh graders passed

Step-by-step explanation:

300 x 0.8 = 240

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6/7 divided by 1 2/5
Alja [10]
In order to multiply or divide a fraction by a mixed numeral, it is best to have them BOTH in fraction form. 1) We'll convert 1 2/5 into an improper fraction. (1×5)+2 = 7/5
Now 6/7 ÷ 7/5
2) when dividing by a fraction, it is the same to multiply by its reciprocal. So flip the second fraction and multiply them: 6/7 ÷ 7/5 = 6/7 × 5/7
3) reduce them: there is nothing on top that reduces with the bottom, so we simply multiply
4) multiply numerators, then multiply denominators and keep them in place: 6×5 = 30, 7×7 = 49
5) so our final answer is 30/49
4 0
2 years ago
Please help me on this one
tester [92]

south America = 2.2%

2.2% = 0.022

0.022 = 22/1000 which reduces to 11/500

4 0
3 years ago
QUESTION IN THE ATTACHMENT
eimsori [14]

Answer:

A. The sum of the first 10th term is 100.

B. The sum of the nth term is n²

Step-by-step explanation:

Data obtained from the question include:

Sum of 20th term (S20) = 400

Sum of 40th term (S40) = 1600

Sum of 10th term (S10) =..?

Sum of nth term (Sn) =..?

Recall:

Sn = n/2[2a + (n – 1)d]

Sn is the sum of the nth term.

n is the number of term.

a is the first term.

d is the common difference

We'll begin by calculating the first term and the common difference. This is illustrated below:

Sn = n/2 [2a + (n – 1)d]

S20 = 20/2 [2a + (20 – 1)d]

S20= 10 [2a + 19d]

S20 = 20a + 190d

But:

S20 = 400

400 = 20a + 190d .......(1)

S40 = 40/2 [2a + (40 – 1)d]

S40 = 20 [2a + 39d]

S40 = 40a + 780d

But

S40 = 1600

1600 = 40a + 780d....... (2)

400 = 20a + 190d .......(1)

1600 = 40a + 780d....... (2)

Solve by elimination method

Multiply equation 1 by 40 and multiply equation 2 by 20 as shown below:

40 x equation 1:

40 x (400 = 20a + 190d)

16000 = 800a + 7600. ........ (3)

20 x equation 2:

20 x (1600 = 40a + 780d)

32000 = 800a + 15600d......... (4)

Subtract equation 3 from equation 4

Equation 4 – Equation 3

32000 = 800a + 15600d

– 16000 = 800a + 7600d

16000 = 8000d

Divide both side by 8000

d = 16000/8000

d = 2

Substituting the value of d into equation 1

400 = 20a + 190d

d = 2

400 = 20a + (190 x 2)

400 = 20a + 380

Collect like terms

400 – 380 = 20a

20 = 20a

Divide both side by 20

a = 20/20

a = 1

Therefore,

First term (a) = 1.

Common difference (d) = 2.

A. Determination of the sum of the 10th term.

First term (a) = 1.

Common difference (d) = 2

Number of term (n) = 10

Sum of 10th term (S10) =..?

Sn = n/2 [2a + (n – 1)d]

S10 = 10/2 [2x1 + (10 – 1)2]

S10 = 5 [2 + 9x2]

S10 = 5 [2 + 18]

S10 = 5 x 20

S10 = 100

Therefore, the sum of the first 10th term is 100.

B. Determination of the sum of the nth term.

First term (a) = 1.

Common difference (d) = 2

Sum of nth term (Sn) =..?

Sn = n/2 [2a + (n – 1)d]

Sn = n/2 [2x1 + (n – 1)2]

Sn = n/2 [2 + 2n – 2]

Sn = n/2 [2 – 2 + 2n ]

Sn = n/2 [ 2n ]

Sn = n²

Therefore, the sum of the nth term is n²

6 0
2 years ago
Mrs. Linda has 17.16 cups of brownie mix. If each
Alex73 [517]

Answer:

52 brownies

Step-by-step explanation:

If you divide 17.16 by 0.33, you get 52

5 0
3 years ago
Find 3√27 +3√64 - 3√125
serg [7]

Answer:

the answer is approximately 6.047

4 0
3 years ago
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