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3 years ago

Americium-241 decays into neptunium-237. Which correctly describes this process of radioactive decay?

2 answers:

4 0

The best and most correct answer among the choices provided by your question is the first choice which is "An unstable nucleus decays into a more stable nucleus."

Radioactive decay (also known as nuclear decay or radioactivity) is the process by which the nucleus of an unstable atom loses energy by emitting radiation, including alpha particles, beta particles, gamma rays, and conversion electrons. A material that spontaneously emits such radiation is considered radioactive.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

Sedaia [141]3 years ago

3 0

Answer:

A. An unstable nucleus decays into a more stable nucleus.

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Write a net ionic equation to show that acetylsalicylic acid (aspirin), hc9h7o4, behaves as a brÃ¸nsted-lowry acid in water.

Thepotemich [5.8K]

By definition, Bronsted-Lowry acid is a proton donor in the acid-base neutralization reaction. When a weak acid like acetylsalicylic acid is reacted with water, the water here acts as the Bronsted-Lowry base. This is possible because water has properties of amphoterism - can act as an acid or base. In this case, acetylsalicylic acid would have to donate its H+ atom to water, so that it would yield a hydronium ion, H₃O⁺. The complete net ionic reaction is shown in the picture.

So, in the reaction, the products yield are the acetylsalicylate ion and the hydronium ion.

3 0

3 years ago

Are elecronegativity values higher for metals than nonmetals.

Leya [2.2K]

Non-metals, which are organized on the right side of the periodic table, have higher electronegativity values than the metals.

Hope this helped!

3 0

3 years ago

a physical property can be observed while the substance remains the same in its chemical composition. true false

sweet [91]

While the material retains its chemical makeup, the physical property may be examined. The given statement is true.

The matter can undergo variations in physical or chemical properties. The physical changes of a matter occur when the matter undergoes changes in its physical properties like changes in the state of matter, weight, color, etc.

But the chemical composition of matter will remain constant if it undergoes a physical change. Whereas in chemical change, the matter undergoes a change in the composition of the substance but there will be no change in the physical properties.

Hence, The assertion is correct in that physical properties can be seen while the substance's chemical makeup stays constant.

To learn more about physical and chemical change, visit: brainly.com/question/21509240

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8 0

1 year ago

The substance water always has a mass ratio of 11% H to 89% O. If 5.00g of a substance containing H and O was decomposed into .2

Gre4nikov [31]

Answer:

No the substance is not water.

Explanation:

The balance chemical equation for the decomposition of water is as follow;

2 H₂O = 2 H₂ + O₂

Step 1: Calculate moles of H₂O;

Moles = Mass / M.Mass

Moles = 5.0 g / 18.01 g/mol

Moles = 0.277 moles of H₂O

Step 2: Calculate Moles of O₂ and H₂ produced by 0.277 moles of H₂O:

According to equation,

2 moles of H₂O produced = 1 mole of O₂

So,

0.277 moles of H₂O will produce = X moles of O₂

Solving for X,

X = 0.277 mol × 1 mol / 2 mol

X = 0.138 moles of O₂

Also,

According to equation,

2 moles of H₂O produced = 2 mole of H₂

So,

0.277 moles of H₂O will produce = X moles of H₂

Solving for X,

X = 0.277 mol × 2 mol / 2 mol

X = 0.227 moles of H₂

Step 3: Calculate Mass of O₂ and H₂ as;

For O₂:

Mass = Moles × M.Mass

Mass = 0.138 mol × 31.99 g/mol

Mass = 4.44 g of O₂

For H₂:

Mass = Moles × M.Mass

Mass = 0.227 mol × 2.01 g/mol

Mass = 0.559 g of H₂

Conclusion:

From conclusion it is proved that the amount of H₂ produced by decomposition of 5 g of water should be 0.559 g while in statement it is less i.e. 0.290 g.

6 0

3 years ago

If a gas is cooled from 343.0 K to 283.15 K and the volume is kept constant what final pressure would result if the original pre

mario62 [17]

Answer:

627.4 mmHg

Explanation:

From Gay-Lussac law:

$\frac{p1}{t1} = \frac{p2}{t2}$