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ArbitrLikvidat [17]
3 years ago
6

Which conditions are necessary for a lunar eclipse to occur?

Chemistry
2 answers:
riadik2000 [5.3K]3 years ago
8 0
It'd be either A or D.
When a lunar eclipse begins, the moon goes in front of the sun and blocks out the sun light, making it completely dark.
vekshin13 years ago
4 0

The answer is B) the moon is in Earth's shadow

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How does induced transmutation produce trans uranium elements ?
kifflom [539]
Answer: Artificial transmutation may occur in machinery that has enough energy to cause changes in the nuclear structure of the elements. This releases, on average, 3 neutrons and a large amount of energy. The released neutrons then cause fission of other uranium atoms, until all of the available uranium is exhausted.
Hope this helped!!
Could I get brainliest by chance?!
5 0
3 years ago
A water bottle has a mass of 14.0g. Given a density of 1.38g/cm^3, what is the volume of the plastic used to make the water bott
Kipish [7]

Answer:

\boxed{\sf Volume \ of \ plastic \ used = 10.14 \ cm^3}

Given:

Mass = 14.0 g

Density (\rho) = 1.38 g/cm³

To Find:

Volume (V)of the plastic used to make water bottle

Explanation:

Formula:

\boxed{ \bold{Density \ (\rho) = \frac{Mass \ (m)}{Volume \ (V)}}}

Substituting value of m & density in the formula:

\sf \implies 1.38 =  \frac{14.0}{V} \\  \\   \sf \implies V =  \frac{14.0}{1.38} \\  \\   \sf \implies V = 10.14 \ cm^3

\therefore

Volume of the plastic used to make water bottle = 10.14 cm³

6 0
3 years ago
To what volume in millimeters must 50.0 mL of 18.0 M H2SO4 be diluted to obtain 4.35 M H2SO4?
poizon [28]
We know that to relate solutions of with the factors of molarity and volume, we can use the equation: M_{1}  V_{1} = M_{2}  V_{2}

**NOTE: The volume as indicated in this question is defined in L, not mL, so that conversion must be made. However it is 1000 mL = 1 L.

So now we can assign values to these variables. Let us say that the 18 M H_{2}  SO_{4} is the left side of the equation. Then we have:

(18 M)(0.050 L)=(4.35M) V_{2}

We can then solve for V_{2}:

V_{2}= \frac{(18M)(0.05L)}{4.35M} and V_{2} =0.21 L or 210 mL

We now know that the total amount of volume of the 4.35 M solution will be 210 mL. This is assuming that the entirety of the 50 mL of 18 M is used and the rest (160 mL) of water is then added.


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Chemical science deals with mater like compound mater 
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Ca (ClO) 2<br> Spell out the full name of the compound.
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