Explanation:
check the steps in the attached image
Answer:
Cannot withstand very high temperature as all plastics melt down very soon as compared to metals
Answer:
D) 0 k.cal per 4 grams
Explanation:
Genarally, glucose can be classified into two enantiomers such as d-glucose and l-glucose. The d-glucose is the most common sugar that bodies of living organisms use as source of energy. However, l-glucose is an organic compound and it is one of the aldohexose monosaccharides. It is the l-isomer of glucose and commonly refer to as a low-calorie sweetener. The l-glucose is relatively indistinguishable in taste from d-glucose but cannot be used as a source of energy. Therefore, in the given problem:
if d-glucose has an estimated caloric value of 1 k.cal per 4 grams of carbohydrate, then the caloric value of l-glucose will be 0 k.cal per 4 grams.
Answer:
Antimony - metalloid
Tungsten- Transition metal
Argon - Noble gas
Iron - Transition metal
Bromine- Halogen
Cesium- Alkali metal
Cerium- lanthanide
Uranium - Actinide
Calcium- Alkaline earth metal
Lithium - Alkaline metal
Explanation:
Lithium is an alkaline metal because it belongs to group 1 of the periodic table. This is the general name for the group.
Calcium is an alkaline earth metal as it belongs to group 2 of the periodic table. This is the general name of the group.
Uranium is an actinide as it belongs to the second series of the f block
Cerium is the second element in the lanthanide series after lanthanum
Cesium belongs to group 1 and hence is an alkaline metal.
Bromine is a halogen as it belongs to group 7 of the periodic table
Iron is a transition metal as it belongs to the first series of transition metals
Argon is s noble gas as it belongs to group 18
Tungsten is s transition element and it belongs to the third series
Antimony is a metalloid
Option C: the electrons are embedded in a positive sphere.
As we know that was a wrong model and nowadays the electrons are considered to be around the nucleus, in regions called orbitals.
