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AnnyKZ [126]
3 years ago
15

Please, help as soon as possible. I'll give brainliest to the first right answer!

Chemistry
2 answers:
Monica [59]3 years ago
6 0

Answer:

A:1amu

B:+1

C: neutron

D:1 amu

Explanation:

because it is

WARRIOR [948]3 years ago
5 0

Answer:A: 1

B: +1

C: Neutron

D: 1

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A) How much energy would be required to melt 500 grams of ice at 0°C to water at 0°C?
baherus [9]

Heat required = Q = 40 kcal

<h3>Further explanation</h3>

Given

mass of 500 g ice

Required

Heat required

Solution

The heat to change the phase can be formulated :  

  • Q = m.Lf (melting/freezing)  
  • Q = m.Lv (vaporization/condensation)  

Lf=latent heat of fusion  

Lv=latent heat of vaporization  

Lf for water = 334 kj/kg=6.01 kJ/mol = 80 cal/g

Phase change(ice to water)

Q=  500 g x 80 cal/g

Q = 40 kcal

4 0
3 years ago
The substitution reaction of toluene with Br2 can, in principle, lead to the formation of three isomeric bromotoluene products.
GREYUIT [131]

Answer:

See explanation and image attached

Explanation:

Aromatic hydrocarbons undergo electrophillic substitution. Usually, substituted benzene is more or less reactive to electrophillic substitution compared to unsubstituted benzene.

Substituents on the benzene ring tend to direct the incoming electrophile during electrophillic substititution. The presence of the -CH3 group on toluene directs the incoming Br electrophile to the ortho/para position.

Where the incoming electrphile E is Bromine, we can see that in the ortho/ para product, the electron pushing -CH3 stabilizes the resonance structure formed and increases electron density at the ortho/para position via resonance compared to the meta product as we can see from the image attached. Hence, the ortho and para products predominate over meta products.

Image credit: Chemistry steps

6 0
3 years ago
P4+O2=P2O3<br> What’s the balance of this equation?
Natasha_Volkova [10]

Explanation:

P₄+O₂=P₂O₃; non-balanced

P₄+O₂=2P₂O₃; to add '2' on the right side; non-balanced

P₄+3O₂=2P₂O₃. to add '3' before O₂ in the left side; balanced

6 0
3 years ago
Can someone answer this for me please
LUCKY_DIMON [66]

years I can answer this question

7 0
3 years ago
Considere la siguiente reacción: H, (g) +1, (a) = 2 HI (9). K, para la reacción es 54.3 a 430°C. Si se coloca H, 0.00623M, 0.004
bearhunter [10]

Answer:

[HI] = 0.0255M

[H₂] = 0.00466M

[I₂] = 0.00257M

Explanation:

Para la reacción:

H₂(g) + I₂(g) ⇄ 2HI(g)

La constante de equilibrio, K, se define como:

54.3 = [HI]² / [H₂] [I₂]

Donde cada concentración [] será la concentración en equilibrio para cada especie

Para saber la dirección del equilibrio definiremos Q como:

Q = [HI]² / [H₂] [I₂]

Donde las concentraciones [] serán las concentraciones actuales de cada gas

Reemplazando:

Q = [0.0224M]² / [0.00623M] [0.00414M]

Q = 19.5

Como Q<K, la reacción se desplazará hacia la derecha produciendo más [HI]. Así, las concentraciones en equilibrio serán:

[HI] = 0.0224M +2X

[H₂] = 0.00623M - X

[I₂] = 0.00414 - X

54.3 = [0.0224M +2X]² / [0.00623M - X] [0.00414M - X]

54.3 = 0.00050176 + 0.0896 X + 4 X² / 0.0000257922 - 0.01037 X + X²

0.00140052 - 0.563091 X + 54.3 X² =  0.00050176 + 0.0896 X + 4 X²

0.00089876 - 0.652691 X + 50.3 X² = 0

Resolviendo la ecuación cuadrática:

X = 0.001566M → Solución verdadera

X = 0.01141M → Falsa solución. Produciría concentraciones negativas

Reemplazando:

[HI] = 0.0224M +2*0.001566M

[H₂] = 0.00623M - 0.001566M

[I₂] = 0.00414 - 0.001566M

[HI] = 0.0255M

[H₂] = 0.00466M

[I₂] = 0.00257M

Siendo estas últimas, las concentraciones de las especies luego de alcanzar el equilibrio.

8 0
3 years ago
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