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alexandr402 [8]
3 years ago
8

Much of the earth’s heat is retained in the crust. wind. oceans. mountains.

Chemistry
2 answers:
pishuonlain [190]3 years ago
7 0
Crust. The crust is closest to the core
mamaluj [8]3 years ago
7 0
Crust because it’s closer to earths core lol
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If an endothermic process absorbs 256j how many kilocalories are absorbed
Finger [1]
There are several units for expressing energy, Most common are joules and kilocalories.

The conversion factor of joule to kilocalories is 
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∴ x kilo calorie = 256 J

x = \frac{256}{4184} = 0.0611 kilo calories

Thus, 256 J = 0.0611 kilocalories
8 0
2 years ago
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Number of grams of hcl that can react with 0.500 grams of Al(OH)3
vlabodo [156]

Answer:

0.7g of HCl

Explanation:

First, let us write a balanced equation for the reaction between HCl and Al(OH)3.

This is illustrated below:

Al(OH)3 + 3HCl —> AlCl3 + 3H2O

Next, let us obtain the masses of Al(OH)3 and HCl that reacted together according to the equation. This can be achieved as shown below:

Molar Mass of Al(OH)3 = 27 + 3(16+1)

= 27 + 3(17) = 27 + 51 = 78g/mol.

Molar Mass of HCl = 1 + 35.5 = 36.5g/mol

Mass of HCl from the balanced equation = 3 x 36.5 = 109.5g

Now we can obtain the mass of HCl that would react with 0.5g of Al(OH)3. This can be achieved as follow:

Al(OH)3 + 3HCl —> AlCl3 + 3H2O

From the equation above,

78g of Al(OH)3 reacted with 109.5g of HCl.

Therefore, 0.5g of Al(OH)3 will react with = (0.5 x 109.5)/78 = 0.7g of HCl

7 0
3 years ago
A Student Formulated A Hypothesis That Cotton Will Grow Larger Bolls ( Pods ) If Magnesium Is Added To The Soil. The Student Has
Sati [7]
Hypothesis is a smart guess that you make on the result of your experiment. You make this even before doing the experiment through inferential analysis. If the hypothesis you made was that, cotton will grow larger balls, then in the experiment, you should measure the cotton boll's size. The size should be in terms of diameter. So, the answer is b.
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If an object has a density of 0.55 g/mL, what is its density in cg/L?
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"cg" is centigram, which is one-hundredth of a gram.

I will first convert from g to cg (multiply by 100), then from mL to L (multiply by 1000).

\frac{0.55g}{mL}*\frac{100cg}{1g}*\frac{1000mL}{1L}=55,000\frac{cg}{L} \ or \ 5.5e4\frac{cg}{L}

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3 years ago
How is this equation read? <br> 4Na (1) +Mn(SO 4 ) 2 (aq) Mn (3) +2Na 2 SO
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