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victus00 [196]
3 years ago
13

Please answer this quick

Mathematics
1 answer:
Darya [45]3 years ago
3 0

(3x + 20degrees )  = 180degrees

180 degress because a stranight angle equals that

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Can i plz have some help with this
inysia [295]

Answer:

320 in

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Which of the following show an element of the sample space for flipping 2 coins? (H= Heads, T= Tails) Check all that apply
Leni [432]

Answer:

All options

Step-by-step explanation:

If two coins are flipped, there are following possibilities

1. Both coins show heads

2. First coin shows heads and second shows tails

3. First coin shows tails and second shows heads

4. Both coins show tails

Let H denote heads and T denote tails

Then the sample space can be translated from the above events as:

Sample  Space for Flipping Two Coins = {HH, HT, TH, TT}

which means that all the options are correct ..

4 0
3 years ago
Read 2 more answers
A relay race is 1 3 4 miles long. Each relay team has 4 runners. If each runner runs the same distance in the race, how far will
Vika [28.1K]

Answer: 7/16

Step-by-step explanation:

Distance of the relay race = 1 3/4 miles

Number of runners for the relay team = 4 runners

Distance to be run by each runner will be:

= Distance of the relay race / Number of runners

= 1 3/4 ÷ 4

= 7/4 ÷ 4

= 7/4 × 1/4

= 7/16

Each runner will run 7/16 miles

6 0
2 years ago
Evaluate 150+n if n=15
IgorLugansk [536]

Answer: 165

Step-by-step explanation: To evaluate this expression, we simply plug the value of the variable into the expression and solve.

So here, since <em>n</em> is equal to 15, we have 150 + (15) which simplifies to 165.

5 0
3 years ago
Read 2 more answers
How do I find the center &amp; radius, then write a standard equation for a,b, and c?
Ghella [55]

Firstly , we will locate centres and radius in the figures

(a)

We can see that

centre=(h,k)=(0,0)

radius=r=5

now, we can use standard equation of circle

(x-h)^2+(y-k)^2=r^2

we can plug values

we get

(x-0)^2+(y-0)^2=5^2

x^2+y^2=25

(b)

We can see that

centre=(h,k)=(5,4)

radius=r=3

now, we can use standard equation of circle

(x-h)^2+(y-k)^2=r^2

we can plug values

we get

(x-5)^2+(y-4)^2=3^2

(x-5)^2+(y-4)^2=9

(c)

We can see that

centre=(h,k)=(4,3)

radius=r=5

now, we can use standard equation of circle

(x-h)^2+(y-k)^2=r^2

we can plug values

we get

(x-4)^2+(y-3)^2=5^2

(x-4)^2+(y-3)^2=25


5 0
3 years ago
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