This is a problem of Standard Normal distribution.
We have mean= 12 grams
Standard Deviation = 2.5 grams
First we convert 8.5 to z score. 8.5 converted to z score for given mean and standard deviation will be:

So, from standard normal table we need to find the probability of z score to be less than -1.4. The probability comes out to be 0.0808
Thus, the <span>
probability that the strawberry weighs less than 8.5 grams is 0.0808</span>
I believe it is B because it makes the most sense
Answer:
Please, see the attached files.
Step-by-step explanation:
Please, see the attached files.
Time = 2*PI* sq root [(length (in metes) / g (9.81 m / sec^2)]
Time = 2 * PI * sq root [(.43) / 9.81]
Time = 2 * PI * sq root [
<span>
<span>
<span>
0.0438328236
</span>
</span>
</span>
]
Time =
<span>
<span>
<span>
6.2832
</span>
</span>
</span>
* (
<span>
<span>
<span>
0.2093628994
</span>
</span>
</span>
)
Time =
<span>
<span>
<span>
1.3155 seconds
</span></span></span>Please see this page about pendulums:
http://www.1728.org/pendulum.htm