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Burka [1]
3 years ago
14

Mr. Rulaski gives $30 to Bailey and Jenny. If Bailey gets twice as much money as Jenny, how much will Jenny get?

Mathematics
1 answer:
Bond [772]3 years ago
3 0
Total amount of money = amount Jenny receives + amount Bailey receives
$30 = 2j + j
30 = 3j
j = $10
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For a particular type of motion, the velocity is zero but the speed is a nonzero quantity. Which statement can you make about th
zhannawk [14.2K]

Keep in mind this relationship

1.  Relationship between Speed, Distance and time

→Distance = Speed × Time

Speed=\frac{Distance}{Time}

2. Relationship between Displacement, Velocity and time

→Displacement = Velocity × Time

Velocity=\frac{Displacement}{Time}

So, velocity is zero only when

Displacement= 0,so when motion is circular motion,

Total Displacement =0 because initial and final position are same.

But , Speed is not zero, because

Total Distance Traveled = 2 π × (Radius of circle).

So, Option (A)The Starting and end point are same  .. . . . in which  the velocity is zero but the speed is a nonzero quantity.




3 0
3 years ago
Read 2 more answers
Quick pls :
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Answer: 20 cups of flour

Step-by-step explanation:

3 0
2 years ago
The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e
Korolek [52]

Answer:

A sample of 499 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

In this question, we have that:

\pi = 0.21

90% confidence level

So \alpha = 0.1, z is the value of Z that has a pvalue of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

How large a sample would be required in order to estimate the fraction of tenth graders reading at or below the eighth grade level at the 90% confidence level with an error of at most 0.03

We need a sample of n, which is found when M = 0.03. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.21*0.79}{n}}

0.03\sqrt{n} = 1.645\sqrt{0.21*0.79}

\sqrt{n} = \frac{1.645\sqrt{0.21*0.79}}{0.03}

(\sqrt{n})^2 = (\frac{1.645\sqrt{0.21*0.79}}{0.03})^2

n = 498.81

Rounding up

A sample of 499 is needed.

8 0
2 years ago
An athlete buys a baseball bat and pays a fee for each baseball lesson taken. The fee for each lesson is the same. The number of
jolli1 [7]

Answer:

The cost of the lessons taken

Step-by-step explanation:

Let

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where

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therefore

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7 0
3 years ago
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REY [17]

$ 6.75/ 1.5 lbs

$4.50 per lb

4 0
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