Answer:
So the answer for this case would be n=107 rounded up to the nearest integer
Step-by-step explanation:
Information given
the sample mean
the sample deviation
the sample size
Solution to the problem
The margin of error is given by this formula:
(a)
And on this case we have that ME =0.001 and we are interested in order to find the value of n, if we solve n from equation (a) we got:
(b)
We can use as estimator of the real population deviation the sample deviation for this case 
/ The critical value for 99% of confidence interval is given by 
, replacing into formula (b) we got:
So the answer for this case would be n=107 rounded up to the nearest integer
This is how i got the result, i hope it is correct!
X + 0.5y = 3
x^2 - y = 15
from the first equation:-
0.5y = 3 - x
y = 6 - 2x
Substitute for y in second equation:-
x^2 - (6 - 2x) = 15
x^2 + 2x - 21 = 0
x = [-2 +/- sqrt((4 - 4*-21)] / 2
= 3.6904 , -5.6904
Plugging in these into first equation we get
3.6904 + 0.5y = 3 so y = 2(3-3.6904) = -1.3808
-5.6904 + 0.5y = 3 so y = 2(3 + 5.6904) = 17.3808
Solution is x = 3.690, y = -1.381 ; x = -5.690, y = 17.38 ( to 4 s.f's)
Answer:
66 mph or 88 mph (I'm a little stuck)
Step-by-step explanation:
Here's how I got this answer:
Conner has to travel 42 miles to get to work.
He left at 7:13 and needs to get to work before 9:30.
If he's going 11 mph for 22 miles, a little less than 2 hours have passed.
If we round up to 2 hours, he has about 15 minutes to get to work.
I multiplied by 22 (the amount of miles he still has left to go) by 2 and got 44. I then realized that would take about 30 minutes (too much time). I did the same thing again but instead I multiplied by 3 and got 66. This is where I got confused. I still can't decide whether the answer is 66 mph, or 88 mph.
(I got the 88 by multiplying 22 by 4.)
(Also, I typed about the same thing in the comments but then typed it out here, too. I would wait for someone else to answer the question or you could choose between the two of my answers and hope for the best haha. You could also email you teacher or someone that could help you!)
Answer:
Can't see it
Step-by-step explanation:
