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Firdavs [7]
3 years ago
12

Measurements show that 1.0 g of iron (Fe) contains 1.1 x 1022 Fe atoms. How many Fe atoms are in 4.9 g of Fe, which is the total

amount of iron in the body of an average adult?
Chemistry
1 answer:
sertanlavr [38]3 years ago
3 0

Answer : The number of iron atoms present in 4.9 grams of iron are, 5.39\times 10^{22}

Explanation : Given,

As we are given that 1.0 grams of iron contains 1.1\times 10^{22} iron atoms.

Now we have to determine the number of iron atoms in 4.9 grams.

As, 1.0 gram of iron contains 1.1\times 10^{22} iron atoms

So, 4.9 gram of iron contains \frac{4.9}{1.0}\times 1.1\times 10^{22}=5.39\times 10^{22} iron atoms

Therefore, the number of iron atoms present in 4.9 grams of iron are, 5.39\times 10^{22}

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