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3 years ago

What quantity of copper is deposited by the same quantity of electricity that deposited 9g of aluminum

Chemistry

1 answer:

klio [65]3 years ago

3 0

Answer:

Mass of copper deposited = 31.75 g

Explanation:

According to Faraday's second law of electrolysis, when the same quantity of electricity is passed through different electrolytes, the relative number of moles of the elements deposited are inversely proportional to the charges on the ions of the elements.

From this law, it can be seen that the higher the charge, the lower the number of moles of a given element deposited.

Number of moles of aluminium in 9 g of aluminium = mass / molar mass

Molar mass of aluminium = 27 g

Number of moles of aluminium = 9/27 = 1/3 moles

Charge on aluminium ion = +3

3 moles of electrons will discharge 1 mole of aluminium,

1 mole of electrons will discharge 1/3 moles of aluminium

Number of moles of electrons involved = 1 mole of electrons

Charge on copper ion = +2

1 mole of electrons will discharge 1/2 moles of copper.

Mass of 1/2 moles of copper = number of moles × molar mass of copper

Molar mass of copper = 63.5 g

Mass of copper deposited = 1/2 × 63.5 = 31.75 g

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You have 16.0 g of some compound and you perform an experiment to remove all of the oxygen, 11.2 g of iron is left. What is the

Makovka662 [10]

The empirical formula of this compound is $Fe_2O_3$

<h3>Empirical formula </h3>

To calculate the empirical formula of a compound, the value of moles of each element is needed.

As we have the information of the mass value, we will use the molar mass expression, which corresponds to:

$MM_O = 16g/mol\\MM_Fe = 55.8g/mol$

$MM = \frac{m}{mol}$

$16 = \frac{4.8}{x}$

$x = 0.3mol$

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As the value of the empirical formula must be an integer, simply multiply the two values by a common factor:

$O = 0.3 \times 10 = 3\\Fe = 0.2 \times 10 = 2$

$Fe_2O_3$

So, the empirical formula of this compound is $Fe_2O_3$ .

Learn more about empirical formula: brainly.com/question/1247523

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2 years ago

How many electrons are in a atom of zicronium

MrRissso [65]

Answer:

There are 40 electrons in one atom of Zirconium.

Explanation:

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Diamond is a natural form of pure carbon. What number of atoms of carbon are in a 1.00-carat diamond (1.00 carat = 0.200 g)?

slega [8]

Answer:

1.004×10²²

Explanation:

The molar mass of carbon is 12 g/mol

which means that:

<u>1 mole of carbon atoms has a mass of 12 grams.</u>

Since, diamond is a allotrope of carbon.

Mass of 1.00-carat diamond in grams is:

1.00 carat = 0.200 g

<u> Since, 1 mole of C contains 6.022×10²³ atoms of C</u>

So,

12 grams contains 6.022×10²³ atoms of C

1 gram contains 6.022×10²³/ 12 atoms of C

0.200 gram contains (6.022×10²³/ 12)×0.200 atoms of C

Thus,

<u>1 carat diamond contains 1.004×10²² atoms of C.</u>

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2 years ago