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3 years ago

What is the right ratio of chemicals for the BCE (Balanced Chemical Equation)?

Chemistry

1 answer:

Reika [66]3 years ago

3 0

2 Ca + 2H2O ⇒ 2 Ca(OH)2 + H2

Explanation: number of atoms of every element

Need to be equal in both sides

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alexandr402 [8]

So the solution inside doesn't splash

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3 years ago

Which form of energy is converted to thermal energy when propane burns in air?

kolezko [41]

Chemical because the propane has stored chemical energy which is being released and a by-product of that propane is heat or themal energy.

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3 years ago

A solution is made by mixing equal masses of methanol, CH 4 O , and ethanol, C 2 H 6 O . Determine the mole fraction of each com

Fynjy0 [20]

Answer:

Mole fraction of $CH_4O$ = 0.58

Mole fraction of $C_2H_6O$ = 0.42

Explanation:

Let the mass of $CH_4O$ and $C_2H_6O$ = x g

Molar mass of $CH_4O$ = 33.035 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles_{CH_4O}= \frac{x\ g}{33.035\ g/mol}$

$Moles_{CH_4O}=\frac{x}{33.035}\ mol$

Molar mass of $C_2H_6O$ = 46.07 g/mol

Thus,

$Moles= \frac{x\ g}{46.07\ g/mol}$

$Moles_{C_2H_6O}=\frac{x}{46.07}\ mol$

So, according to definition of mole fraction:

$Mole\ fraction\ of\ CH_4O=\frac {n_{CH_4O}}{n_{CH_4O}+n_{C_2H_6O}}$

$Mole\ fraction\ of\ CH_4O=\frac{\frac{x}{33.035}}{\frac{x}{33.035}+\frac{x}{46.07}}=0.58$

Mole fraction of $C_2H_6O$ = 1 - 0.58 = 0.42

6 0

4 years ago

A horizontal pipe 15 cm in diameter and 4 m long is buried in the earth at a depth of 20 cm. The pipe-wall temperature is 75 deg

Basile [38]

Explanation:

The given data for case (1) is as follows.

h = 20 cm = 0.2 m

Assuming that a rectangular slab is placed above the pipe and we will calculate the heat transfer as follows.

Q = $kA \frac{\Delta T}{L}$

where, A = area

L = length

k = thermal conductivity = 0.8 W/m

$\Delta T$ = change in temperature.

Therefore, putting the given values into the above formula as follows.

Q = $kA \frac{\Delta T}{L}$

= $0.8 W/m \times (4 m \times 0.15 m) \frac{75 - 5}{0.2}$

= 168 W

For case (2), h = 180 cm = 1.8 m

Therefore, heat lost will be calculated as follows.

Q = $kA \frac{\Delta T}{L}$

= $0.8 W/m \times (4 m \times 0.15 m) \frac{75 - 5}{1.8}$

= 18.67 W

Thus, we can conclude that 18.67 W heat lost if the pipe was buried at a depth of 180 cm.

8 0

3 years ago

A bobsled has a momentum of 4000 0 kg* m/s to the south. Friction on the track reduces its momentum to 500 kg* m/s to the south.

faltersainse [42]

The correct answer is c

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3 years ago

Read 2 more answers