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ozzi
3 years ago
9

When trees transpire, releasing gaseous water into the atmosphere, they can absorb heat from their environment and cool it down.

What property of water is responsible for this activity?
A) High heat capacity.
B) High heat of vaporization.
C) Adhesion.
Biology
2 answers:
Valentin [98]3 years ago
8 0
The right answer for the question that is being asked and shown above is that: "B) High heat of vaporization." When trees transpire, releasing gaseous water into the atmosphere, they can absorb heat from their environment and cool it down. The property of water that is responsible for this activity is that h<span>igh heat of vaporization.</span>
Usimov [2.4K]3 years ago
8 0
<span>As we already know the biosphere are all living things which include animals and plants. The Geosphere is all the solid earth parts like rocks, mountains, soils and landforms. The atmosphere are all the gases that surround our planet. The way the biosphere facilitates movement of water from the geosphere to the atmosphere is evaporation. The water evaporates from inside the soils through the vegetation and from the revers, lakes and oceans. This evaporated water accumulates as water vapor in the atmosphere and then comes back to the geosphere and biosphere.

Answer: B) High heat of vaporization.

I hope it helps, Regards.</span>
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How do populations interact within and between trophies levels
ololo11 [35]

Answer:

Explanation:

A trophic level is a set of organisms who all have similar nutritional needs. In a food web, secondary consumers, such as fox and birds of prey, are on the same trophic level. How do different populations from the same trophic level interact? Different populations on the same trophic level can compete for food.

4 0
3 years ago
A recessive allele on the X chromosome is responsible for red-green color blindness in humans. A woman with normal vision whose
Igoryamba

Answer:

In a cross of a homozygous prevailing (AA) individual and a homozygous recessive(AA) person,  

a. on the off chance that they have a kid, what is the likelihood that the kid will be heterozygous?  

If you cross somebody who is homozygous predominant with one who is homozygous latent, the entirety of the posterity will be heterozygous (AA). Accordingly, there is a 100% possibility of delivering a posterity that is heterozygous.  

b. what is the likelihood that the youngster will be homozygous latent?  

There is no way of creating a kid that is homozygous passive. The entirety of the posterity will be heterozygous. In this way, the likelihood is zero.  

c. in the event that they have two kids, what is the likelihood of the first being homozygous prevailing and the second being homozygous passive?  

Again, this can't be determined, on the grounds that there is zero chance of delivering a posterity that is homozygous prevailing or homozygous passive. The likelihood is zero. In any case, for no reason in particular, suppose that the punnet square uncovered that there was 1/4 possibility of creating a kid that is homozygous passive. To decide the likelihood that the subsequent youngster will likewise be homozygous passive, you complete this straightforward duplication:  

1/4 x 1/4 = 1/16  

In this manner, there would be a 1/16 possibility of the subsequent kid being homozygous passive. In the event that you needed to discover the likelihood of the third kid being homozygous passive, you would do the accompanying:  

1/4 x 1/4 x 1/4 = 1/64  

Thus, there would be a 1/64 possibility of the third kid being homozygous latent. Once more, I was simply giving in model, yet it doesn't have any significant bearing right now, the entirety of the posterity will be heterozygous.  

Another question...A latent allele on the X chromosome is answerable for red-green visual weakness in people. A typical lady whose father is visually challenged weds a partially blind man. What is the likelihood that this couples child will be visually challenged?  

XX = female  

XY = male  

Let C = typical vision (predominant)  

Let c = red-green visual weakness (latent)  

A typical lady what father's identity is' partially blind must be a transporter, or heterozygous. This implies she acquired the ordinary allele from her mom and the visually challenged allele from her dad.  

Genotypes:  

Ordinary lady - Xc  

Partially blind man - Xc Y  

On the off chance that these two mate, here are the accompanying prospects:  

half of the female posterity will be bearers with ordinary vision (Xc)  

half of the female posterity will be homozygous passive and partially blind (Xc)  

half of the male posterity will have typical vision (XC Y)  

half of the male posterity will be visually challenged (Xc Y)  

In this manner, the likelihood that the couple's child will be partially blind is half, or 1/2.  

Remark  

Sheryl's Avatar  

Sheryl addressed this Was this answer accommodating?  

XX= lady, XY=man  

Alleles:  

XC=normal; Xc=colorblind  

Typical Genotypes:  

XC (typical lady)  

Xc (typical lady, yet bearer)  

Xc (visually challenged lady)  

XC Y (typical man)  

Xc Y (visually challenged man)  

Lady has typical vision, yet her dad is visually challenged. In this way, she needed to get XC from her mother (must have one, she's ordinary) and Xc from her father (it was everything he could give her): Xc  

Man is visually challenged: Xc Y  

Xc Y  

XC Y  

Xc Y

6 0
4 years ago
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ICE Princess25 [194]

Answer:

c. the sun

Explanation:

The sun is the most basic source of energy for all living beings. It supports photosynthesis in plants and algae that is the main reaction for producing energy rich compounds like carbohydrates etc. These compounds are utilized by all life on Earth to stay alive.

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Need help ?.........
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you find a litter of cats both parents and fathers cast of black you notice that 2 out of 8 or white how is this possible​
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Maybe there was another dad
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