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2 years ago

An isosceles triangle has an angle that measures 138º. Which other angles could be in that

Mathematics

1 answer:

sergiy2304 [10]2 years ago

7 0

Answer:

Let the two equal angles be x,

so,

x + x + 138° = 180°

or, 2x = 180° - 138°

or, 2x = 42°

so, x = 42°/2

so, x = 21°

21° is the answer.

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The width of a rectangle is 7 less than it’s length. Which expression represents the perimeter of the rectangle with a length of

JulsSmile [24]

Short answer = 4x-14

See attached image for worked solution.

I hope this helped!

3 0

2 years ago

How do you write –51. 6 as a mixed nuber

Ganezh [65]

Answer:

-51 6/10 or -51 60/100

Step-by-step explanation:

4 0

2 years ago

A circle with a radius of 1 unit

oee [108]

Answer:

C= 6.28 A: 3.14

Step-by-step explanation:

Circumference of a circle is 2* pi * r

Based on this, we can subsitute r for 1

2* pi * 1= 2pi which is around 6.28 units

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8 0

2 years ago

Answer correct for brainliest and also get a thanks ! :-) please help !!

GREYUIT [131]

Y =2x +14

-4x –y = 4 so y = -4x – 4

2x + 14 = -4x – 4

2x + 4x = -4 - 14

6x = -18

x = -18/6

x = -3

Y =2x +14

y = 2(-3) +14

y= -6 +14

y=8

answer:

y-coordinate is 8

3 0

3 years ago

PLs help 50 PTS!!!!! PLEASE ILL GIVE BRAINLIEST!!!!!

Nookie1986 [14]

Answer:

$\large\boxed{y=\dfrac{1}{4}x^2-x-4}$

Step-by-step explanation:

The equation of a parabola in vertex form:

$y=a(x-h)^2+k$

(h, k) - vertex

The focus is

$\left(h,\ k+\dfrac{1}{4a}\right)$

We have the vertex (2, -5) and the focus (2, -4).

Calculate the value of a using $k+\dfrac{1}{4a}$

k = -5

$-5+\dfrac{1}{4a}=-4$ add 5 to both sides

$\dfrac{1}{4a}=1$ multiply both sides by 4

$4\!\!\!\!\diagup^1\cdot\dfrac{1}{4\!\!\!\!\diagup_1a}=4$

$\dfrac{1}{a}=4\to a=\dfrac{1}{4}$

Substitute

$a=\dfrac{1}{4},\ h=2,\ k=-5$

to the vertex form of an equation of a parabola:

$y=\dfrac{1}{4}(x-2)^2-5$

The standard form:

$y=ax^2+bx+c$

Convert using

$(a-b)^2=a^2-2ab+b^2$

$y=\dfrac{1}{4}(x^2-2(x)(2)+2^2)-5\\\\y=\dfrac{1}{4}(x^2-4x+4)-5$

use the distributive property: a(b+c)=ab+ac

$y=\left(\dfrac{1}{4}\right)(x^2)+\left(\dfrac{1}{4}\right)(-4x)+\left(\dfrac{1}{4}\right)(4)-5\\\\y=\dfrac{1}{4}x^2-x+1-5\\\\y=\dfrac{1}{4}x^2-x-4$

3 0

3 years ago