Ask question

Ask question

All categories

3 years ago

15

ILL GIVE U BRAINLYIST IF U ANSWER. Find the solution to the system of equations below (you can do this by substitution or elimin

ation).
-4x+y=6
-5x-y=21

1 answer:

cricket20 [7]3 years ago

7 0

Elimination:

-4x+y=6

-5x-y=21 ...and then u add them together so its;

(the y cancelled out so its 0) x =27

plug in the 27 to any x...

-4(27) + y = 6

-108+y=6

add -108 on both sides so its...

y= -102

(27, -102)

Hope this helped :)

You might be interested in

Given the following diagram, find the missing measure.<br> m<1=30, m<2=45, m<3=

Mice21 [21]

I believer it is m3= 105

4 0

3 years ago

Select the correct answer.

oee [108]

Answer:

a² + b² = c²

Step-by-step explanation:

Pythagorean theorem: a² + b² = c²

3 0

3 years ago

Solve 2(x-1) =4 xxxxxx

sineoko [7]

2(x-1)=4
2x-2=4
2x=6
x=3

4 0

3 years ago

A tennis tournament has 2n contestants. We want to pair them up for the first round of singles matches. Show that the number of

ddd [48]

There are

$\dbinom{2n}2 = \dfrac{(2n)!}{2! (2n-2)!}$

ways of pairing up any 2 members from the pool of $2n$ contestants. Note that

$(2n)! = 1\times2\times3\times4\times\cdots\times(2n-2)\times(2n-1)\times(2n) = (2n-2)! \times(2n-1) \times(2n)$

so that

$\dbinom{2n}2 = \dfrac{(2n)\times(2n-1)\times(2n-2)!}{2! (2n-2)!} = \boxed{n(2n-1)}$

4 0

2 years ago

4(5 -3y) please show steps!!

Damm [24]

Answer : 20 - 12y

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers