Answer:
x=1
Step-by-step explanation:
According to your typed question,
f(x)=2x-3
Let f(x)=y
y=2x-3
Now,
Interchanging the positions of x and y
x=2y-3
x+3=2y
x+3/2=y
f'(x)=x+3/2
Then,
f(x)=f'(x)
2x-3=x+3/2
2(2x-3)=x+3
4x-3=x+3
4x-x=3+3
3x=3
x=3/3
x=1
According to your image question,
f(x)=x/2x-3
f(x)=f'(x)
Now,
Let y=f(x)
y=x/2x-3
y(2x-3)=x
2xy-3=x
2xy-x=3
x(2y-1)=3
2y-1=3x
2y=3x+1
y=3x+1/2
f'(x)=3x+1/2
Then,
f(x)=f'(x)
x/2x-3=3x+1/2
2x=6xsq+2x-9x+3
2x=6xsq+7x+3
solve for x ok
You have to Multiply times 3...
12•3=36
36/12=3
1 inch= 2.54
6 inch= 15.24 becuase 2.54*6=15.24
Hope this helps!!
First, distribute the 12
156-168-15=16+4+x
-27=20+x
-47=x
Answer:
x = 1
, y = 3 thus: A is your Anser
Step-by-step explanation:
Solve the following system:
{2 x + y = 5 | (equation 1)
x + y = 4 | (equation 2)
Subtract 1/2 × (equation 1) from equation 2:
{2 x + y = 5 | (equation 1)
0 x+y/2 = 3/2 | (equation 2)
Multiply equation 2 by 2:
{2 x + y = 5 | (equation 1)
0 x+y = 3 | (equation 2)
Subtract equation 2 from equation 1:
{2 x+0 y = 2 | (equation 1)
0 x+y = 3 | (equation 2)
Divide equation 1 by 2:
{x+0 y = 1 | (equation 1)
0 x+y = 3 | (equation 2)
Collect results:
Answer: {x = 1
, y = 3
