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Brrunno [24]
3 years ago
12

What is (f+g)(x)?

Mathematics
2 answers:
Ainat [17]3 years ago
6 0

Answer:

(f+g)(x)=x^{3}+3x^{2}  -46

Step-by-step explanation:

The given functions are

f(x)=x^{2} -36\\g(x)=x^{3}+2x^{2}  -10

Now, the operation (f+g)(x) indicates that we need to sum these functions. As polynomials, we can sum terms with equal grade. so,

(f+g)(x)=x^{3} +(2+1)x^{2} -10-36=x^{3}+3x^{2}  -46

Therefore, the answer is (f+g)(x)=x^{3}+3x^{2}  -46

Goryan [66]3 years ago
3 0

Answer:

(f+g)(x) = x^3 + 3x^2 - 46.

Step-by-step explanation:

(f+g)(x) means to add the like terms in each function together.

So (f+g)(x) = x^2 - 36 + x^3 + 2x^2 - 10 = x^3 + 3x^2 - 46

So (f+g)(x) = x^3 + 3x^2 - 46.

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It is in simplest form

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The greatest common factor of 56 f^3g^2 and 70 fg^3 is 7 fg^3 .<br> true or false
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The average undergraduate cost for tuition, fees, and room and board for two-year institutions last year was $13,252. The follow
kipiarov [429]

Answer:

The p-value of the test is 0.0041 < 0.05, which means that there is sufficient evidence at the 0.05 significance level to conclude that the mean cost has increased.

Step-by-step explanation:

The average undergraduate cost for tuition, fees, and room and board for two-year institutions last year was $13,252. Test if the mean cost has increased.

At the null hypothesis, we test if the mean cost is still the same, that is:

H_0: \mu = 13252

At the alternative hypothesis, we test if the mean cost has increased, that is:

H_1: \mu > 13252

The test statistic is:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

13252 is tested at the null hypothesis:

This means that \mu = 13252

The following year, a random sample of 20 two-year institutions had a mean of $15,560 and a standard deviation of $3500.

This means that n = 20, X = 15560, s = 3500

Value of the test statistic:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{15560 - 13252}{\frac{3500}{\sqrt{20}}}

t = 2.95

P-value of the test and decision:

The p-value of the test is found using a t-score calculator, with a right-tailed test, with 20-1 = 19 degrees of freedom and t = 2.95. Thus, the p-value of the test is 0.0041.

The p-value of the test is 0.0041 < 0.05, which means that there is sufficient evidence at the 0.05 significance level to conclude that the mean cost has increased.

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because it's either the lowest or highest point on the graph.

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Yes it will occur because two tenths of a mile the second relay will exchange 
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