The information given is sufficient for this proof .
Slope of a line passing through x1 ,y1) and ( x2,y2) is given by the formula :
M = ( y2 - y1)/ ( x2-x1)
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Let us start finding the slope of line PQ
the given points are ( a,b) and ( c,d)
using the slope formula we get :
slope of line PQ = m= ( d-b) /( c-a)
Let us now try finidng slope of the another line P'Q'
It is passing through ( -b ,a) and (-d,c)
using the formula we get slope of P'Q' = m' = ( c-a) /( -d - -b)
m'= ( c-a) /( -d+b)
m'= ( c-a) / -( b-d Let us find the product of m and m' :
( d-b ) * ( c-a)
----------- ------------ = -1
(c-a) - ( b-d)
Because we got product of m and m' = -1 hence proved product of perpendicular lines are negative reciprocal of each other .
Answer:
180 degree rotation about the origin.
Step-by-step explanation:
Note that each coordinate ( x and y) have their sign changed form positive to negative. This is a rotation about the origin of 180 degrees.
-3/4 is the slope.
Explanation: if we use the formula y2- y1/ x2-x1= m (m being the slope) we get -3/4.
X2 + 5x - 6 =0
(x +6)(x-1)=0
Answer:
hi
Step-by-step explanation:
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