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zubka84 [21]
3 years ago
15

identify a transformation of the function f(x) = √x by observing the equation of the function g(x) = √x-2

Mathematics
2 answers:
MA_775_DIABLO [31]3 years ago
8 0

Answer:

<h2>The transfomation made is a vertical translation 2 units downwards.</h2>

Step-by-step explanation:

The parent function is

f(x)=\sqrt{x}

Remember that a parent function is the simplest function of its type, like this case the function f(x) is the simplest form of radical functions.

The transformed function is

g(x)=\sqrt{x}-2

Notice that the difference between these two functions is that g(x) has 2 units less on the vertical or dependent variable, such transformation indicates a vertical translation downwards.

Therefore, the transfomation made is a vertical translation 2 units downwards.

gregori [183]3 years ago
7 0
<h2>Answer:</h2>

f(x)=\sqrt{x} is the Square Root Function. These are the characteristics of the graph of the square root function:

  • The domain of the function is the set of all non negative real numbers.
  • The range of the function is the set of all non negative real numbers.
  • The graph has an intercept at (0,0).
  • The graph is increasing on the interval (0, \infty).

Since the function g(x)=\sqrt{x}-2, then this stands for the form:

g(x)=f(x)-c. This form tells us that the graph of f has been shifted c units downward where the value c = 2 in this problem. The graphs of both functions are shown below. The red one is f(x) while the blue one is g(x)

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3 years ago
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8 0
2 years ago
Please please please help. thank you.
djverab [1.8K]
Lets get started :)


The First question:
Diameter = 20 ft
Radius = \frac{1}{2} of 20 (diameter) = 20 ft

Area formula of a circle is
A = \pir²
    =\pi(10)²
    =100\pi ft²
    ≈ 314 ft²

The answer will be the second option

The Second question:
radius of circle = 12mm  divided into 20 sectors area

A = \pir²
   = \pi(12)²
   = 144\pi ft²

Divide into 20 equal sector areas = \frac{144 \pi }{20} = 7.2 \pi

≈ 22.6 mm²

Your answer will be the third option

The Third Question:

90°, sector area = 36\pi , Radius = ?

\frac{angle}{360} = \frac{sector}{ \pi (r)^2}
\frac{90}{360} = \frac{36 \pi }{ \pi r^2}
\pi and \pi cancels out

We can now cross multiply
360 × 36 = 90r²
12960 = 90r²

Divide by 90 on either side

\frac{12960}{90} = \frac{90r^2}{90}
144 = r²

Take squareroot 
 \sqrt{144} = x
x = 12 in

Your answer will be the third option




4 0
3 years ago
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