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3 years ago

13

PLS HELP

2 answers:

dybincka [34]3 years ago

6 0

12.826+2.93= 15.756

Since you have to round it, your final answer would be 15.8

Olenka [21]3 years ago

4 0

Answer:

15.8

Step-by-step explanation:

Well if you had to round to the nearest tenth then 12.896 would be 12.9 and 2.93 would be 2.9. The reason is if it is below 5 then you would round down if it is more than 5 then round up. Then add the two numbers which are 12.9+2.9=15.8

Hope it helps. Sorry if it does not!

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Apply the distributive property to create an equivalent expression.

Anika [276]

Hi there!

»»————-　★　————-««

I believe your answer is:

$a-3b+4$

»»————-　★　————-««

Here’s why:

⸻⸻⸻⸻

$\boxed{\text{Simplifying the Equation...}}\\\\\frac{1}{2}(2a-6b+8)\\----------------\\\rightarrow\frac{1}{2}* 2a = a\\\\ \rightarrow\frac{1}{2}*-6b = -3b\\\\\rightarrow\frac{1}{2}*8 = 4\\\\\text{\underline{Therefore:}}\\\\\frac{1}{2}(2a-6b+8)\rightarrow \boxed{a-3b+4}$

⸻⸻⸻⸻

»»————-　★　————-««

Hope this helps you. I apologize if it’s incorrect.

4 0

3 years ago

Please help me with this question ASAP

valentina_108 [34]

Answer:

$volume \: = \: \frac{1}{2} \times 6 \times 7 \times 16 \\ = 896$

Hope it helps

5 0

3 years ago

Multiply the binomials (5x+3) And (2x+4)

Sav [38]

Answer:

(5x+3)(2x+4)=10x^2+26x+12

Step-by-step explanation:

You use FOIL (First, Outer, Inner Last)

First: 5x times 2x= 10x^2

Outer: 5x times 4= 20x

Inner: 3 times 2x= 6x

Last= 3 times 4

Combine 20x and 2x to get 26x

3 0

3 years ago

A paint company claims their paint will be completely dry within 45 minutes after application. Recently, customers have complain

Angelina_Jolie [31]

Answer:

The probability of observing a sample mean of x = 52 or greater from a sample size of 25 is 0.0000026

Step-by-step explanation:

Mean = $\mu = 45$

Population standard deviation = $\sigma = 6$

Sample size = n =25

Sample mean = $\bar{x} = 52$

We are supposed to find the probability of observing a sample mean of x = 52 or greater from a sample size of 25 i.e. $P(x\geq 52)$

$Z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}\\Z=\frac{52-45}{\frac{6}{\sqrt{25}}}$

Z=5.83

P(Z<52)=0.9999974

$P(Z\geq 52)=1-P(z$

Hence the probability of observing a sample mean of x = 52 or greater from a sample size of 25 is 0.0000026

3 0

3 years ago

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goblinko [34]

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5 0

3 years ago