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3 years ago

Original price:$119.00;markdown: 70%

1 answer:

6 0

If the question you're trying to ask is what is 70% off something that is $119.00 , then the answer would be $35.7 .

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You are considering a certain telephone company. They charge $0.17 per minute of talking, plus a fixed base monthly fee of $40 .

brilliants [131]

Answer:

C = 40 + 0.17M

Step-by-step explanation:

Total monthly charge = Fixed base fee + charge per minute*total number of minutes

C = 40 + 0.17*M

C = 40 + 0.17M

8 0

3 years ago

You and your brother are reading the same novel. You want to get ahead of him in the book, so you decide to read 30 minutes long

Sholpan [36]

Answer: its 45 if i read it right.

Step-by-step explanation:

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3 years ago

Which inequality does the graph represent?

polet [3.4K]

It would have to be number 2 if it's a dotted line, all the other options are incorrect unless you made a mistake with one or two of the symbols.

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3 years ago

Mrs. Williams needed to make 4 1/2 of fruit salad for a class party.

ziro4ka [17]

Answer:

strawberry=7/8

Step-by-step explanation:

treat strawberry as x

add on proportions

1 1/8+ 3/4+ 1 3/4 + x = 4 1/2

(9+6+14)/8 + x = 9/2

29/8 +x = 9/2

x= 9/2 - 29/8

x= (36-29)/8

x=7/8

3 0

3 years ago

A company wants to establish that the mean life of its batteries, when used in a wireless mouse, is over 183 days. The data will

enyata [817]

Answer:

a) Null and alternative hypotheses are:

$H_{0}$ : mu=183 days

$H_{a}$ : mu>183 days

b) If the true mean is 190 days, Type II error can be made.

Step-by-step explanation:

Let mu be the mean life of the batteries of the company when it is used in a wireless mouse

Null and alternative hypotheses are:

$H_{0}$ : mu=183 days

$H_{a}$ : mu>183 days

Type II error happens if we fail to reject the null hypothesis, when actually the alternative hypothesis is true.

That is if we conclude that mean life of the batteries of the company when it is used in a wireless mouse is at most 183 days, but actually mean life is 190 hours, we make a Type II error.

4 0

3 years ago