An assembly line consists of 21 tasks grouped into 5 workstations. The sum of the 21 task times is 85 minutes. The largest assig
1 answer:
Answer:
The efficiency of this line is 0.85 = 85%.
Step-by-step explanation:
Efficiency:
The efficiency is given by the following formula:
In which is the total task time,
is the largest assigned cycle time and n is the number of workstations.
5 workstations
This means that
The sum of the 21 task times is 85 minutes.
This means that
The largest assigned cycle time is 20 minutes.
This means that
What is the efficiency of this line?
The efficiency of this line is 0.85 = 85%.
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The rule of scientifinc notation is that we can use number between 0 and 10, so here we can use 2.8. Lets do this
280 000 000 = 2.8 * 100 * 1 000 000
Now we can just multiply 2.8 by 10 to the power of number of 0 reapeted
So
- its the result
280 000 000 = 2.8 * 100 * 1 000 000
Now we can just multiply 2.8 by 10 to the power of number of 0 reapeted
So
Draw ΔABC as shown in the figure below.
m∠B = 137°, b = 14, c = 9.
From the Law of Sines,
sin(C)/c = sin(B)/b
or
sin(C)/9 = sin(137°)/14
sin(C) = (9/14)*sin(137°) = 0.4384
m∠C = arcsin(0.4384) = 26°
Because the sum of angles in a triangle is 180°, therefore
m∠A = 180 -137 - 26 = 17°
From the Law of Sines,
a/sin(A) = b/sin(B)
or
a/sin(17°) = 14/sin(137°)
a = (sin(17°)/sin(127°))*14 = 6
Answer:
The solution for the triangle is
a = 6, b = 14, c = 9
m∠A = 17°, m∠B = 137°, m∠C = 26°
m∠B = 137°, b = 14, c = 9.
From the Law of Sines,
sin(C)/c = sin(B)/b
or
sin(C)/9 = sin(137°)/14
sin(C) = (9/14)*sin(137°) = 0.4384
m∠C = arcsin(0.4384) = 26°
Because the sum of angles in a triangle is 180°, therefore
m∠A = 180 -137 - 26 = 17°
From the Law of Sines,
a/sin(A) = b/sin(B)
or
a/sin(17°) = 14/sin(137°)
a = (sin(17°)/sin(127°))*14 = 6
Answer:
The solution for the triangle is
a = 6, b = 14, c = 9
m∠A = 17°, m∠B = 137°, m∠C = 26°