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o-na [289]
3 years ago
15

The manager of a theater noted that for every 10 admission tickets sold, the theater sells 3 bags of popcorn at $2.25 each, 4 so

das at $1.50 each, and 2 candy bars at $1.00 each. To the nearest cent, what is the average (arithmetic mean) amount of these snack sales per ticket sold?
Mathematics
1 answer:
Shalnov [3]3 years ago
5 0

Answer:

$1.475 is the average amount of snack sales per ticket sold.

Step-by-step explanation:

We are given the following in the question:

Number of popcorn bags sold = 3

Cost of  a popcorn bag = $2.25

Total cost of popcorn bag = 2.25\times 3 = $6.75

Number of soda sold = 4

Cost of  a soda = $1.50

Total cost of soda = 1.50\times 4 = $6.00

Number of candy bars sold = 2

Cost of  a candy bar = $1.00

Total cost of candy bars =  1.00\times 2 = $2.00

Total sales =

Total cost of popcorn + Total cost of soda + Total cost of candy bar

= 6.75 + 6 + 2\\=\$14.75

\text{Average} = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Average amount of snack sales per ticket sold =

\dfrac{\text{Total sales}}{\text{Number of tickets}} = \dfrac{14.75}{10} = 1.475

Thus, $1.475 is the average amount of snack sales per ticket sold.

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3 years ago
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Answer: (-1,4)

Step-by-step explanation:

y=-2x+2                                    y=7x+11 <----- substitute this equation for y in the            

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x=-1

y=-2(-1)+2                   Plug in x to one of the equations, I chose y=-2x+2            

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5 0
3 years ago
11. A sample of n = 25 scores has a mean of M = 68. Find the z-score for this sample: a. If it was obtained from a population wi
storchak [24]

Answer:

a) z-score = 4

b) z-score = 2

c) z-score = 1

Step-by-step explanation:

* Lets revise some definition to solve the problem

- The mean of the distribution of sample means is called M

- The standard deviation of the distribution of sample means is

  called σM (standard error)

- σM = σ/√n , where σ is the standard deviation and n is the sample size

- z-score = (M - μ)/σM, where μ is the mean of the population

* Lets solve the problem

∵ The sample size n = 25

∵ The sample mean M = 68

a)

∵ The mean of population μ = 60

∵ The standard deviation σ = 10

- Lets find σM to find z-score

∵ σM = σ/√n

∴ σM = 10/√25 = 10/5 = 2

- Lets find z-score

∵ z-score = (M - μ)/σM

∴ z-score = (68 - 60)/2 = 8/2 = 4

* z-score = 4

b)

∵ The mean of population μ = 60

∵ The standard deviation σ = 20

- Lets find σM to find z-score

∵ σM = σ/√n

∴ σM = 20/√25 = 20/5 = 4

- Lets find z-score

∵ z-score = (M - μ)/σM

∴ z-score = (68 - 60)/4 = 8/4 = 2

* z-score = 2

c)

∵ The mean of population μ = 60

∵ The standard deviation σ = 40

- Lets find σM to find z-score

∵ σM = σ/√n

∴ σM = 40/√25 = 40/5 = 8

- Lets find z-score

∵ z-score = (M - μ)/σM

∴ z-score = (68 - 60)/8 = 8/8 = 1

* z-score = 1

3 0
3 years ago
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