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gladu [14]
3 years ago
8

A company did a quality check on all the packs of roasted almonds it manufactured. Each pack of roasted almonds is targeted to w

eigh 21.25 oz. A pack must weigh within 0.24 oz of the target weight to be accepted. What is the range of rejected masses, x, for the manufactured roasted almonds?
x < 21.01 or x > 21.49 because |x − 0.24| + 21.25 > 0
x < 21.25 or x > 21.49 because |x − 21.25| > 0.24
x < 21.01 or x > 21.49 because |x − 21.25| > 0.24
x < 21.25 or x > 21.49 because |x − 0.24| + 21.25 > 0
Mathematics
1 answer:
user100 [1]3 years ago
4 0

<u>Answer:</u>

x < 21.01 or x > 21.49 because |x - 21.25| > 0.24

<u>Step-by-step explanation:</u>

We know that each pack of almonds is targeted to weigh 21.25 oz.and a pack must weigh within 0.24 oz of the target weight to be accepted.

Assuming x to be the weight of a given pack of almonds, we can write it as:

|x-21.25| > 0.24

Now finding the range of rejected masses (x) of the almonds.

|x-a| >b

-b

|x-21.25| >0.24

-0.24>(x-21.25)>0.24

-0.24>x-21.25 or x-21.25>0.24

x or x>21.49

Therefore, the correct answer option is x < 21.01 or x > 21.49 because |x - 21.25| > 0.24.

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The CEO of a large manufacturing company is curious if there is a difference in productivity level of her warehouse employees ba
blsea [12.9K]

Answer:

The test statistic is z = -2.11.

Step-by-step explanation:

Before finding the test statistic, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

Group 1: Sample of 35, mean of 1276, standard deviation of 347.

This means that:

\mu_1 = 1276, s_1 = \frac{347}{\sqrt{35}} = 58.6537

Group 2: Sample of 35, mean of 1439, standard deviation of 298.

This means that:

\mu_2 = 1439, s_2 = \frac{298}{\sqrt{35}} = 50.3712

Test if there is a difference in productivity level.

At the null hypothesis, we test that there is no difference, that is, the subtraction is 0. So

H_0: \mu_1 - \mu_2 = 0

At the alternate hypothesis, we test that there is difference, that is, the subtraction is different of 0. So

H_1: \mu_1 - \mu_2 \neq 0

The test statistic is:

z = \frac{X - \mu}{s}

In which X is the sample mean, \mu is the value tested at the null hypothesis and s is the standard error.

0 is tested at the null hypothesis:

This means that \mu = 0

From the two samples:

X = \mu_1 - \mu_2 = 1276 - 1439 = -163

s = \sqrt{s_1^2+s_2^2} = \sqrt{58.6537^2+50.3712^2} = 77.3144

Test statistic:

z = \frac{X - \mu}{s}

z = \frac{-163 - 0}{77.3144}

z = -2.11

The test statistic is z = -2.11.

7 0
3 years ago
1,995,298 rounded to the nearest ten thousand
ss7ja [257]
200,000,000 that your answer

6 0
3 years ago
Read 2 more answers
A cylinder has a base with a radius of 5 cm and a height of 15 cm. What is the volume of the cylinder? (Use π = 3.14.) A. 471 cm
eduard
The formula for volume is
V=\pi r^{2}h
We plug in:
V=\pi (5)^{2}(15)
=\pi (25)(15)
=375\pi
=375*3.14=1177.5
5 0
4 years ago
Read 2 more answers
About how many u.s dollars would you get if you exchange 15 euros
Free_Kalibri [48]

Answer:

16 dollars and 32 cents

Step-by-step explanation:

8 0
3 years ago
The scale of a model train is 1 inch to 13.5 ft. One of the cars of the model train is 5inches long. What is the length in feet
aleksklad [387]

Answer:

The length of the actual train's car is <u>67.5 feet.</u>

Step-by-step explanation:

Given:

The scale of a model train is 1 inch to 13.5 ft.

Now, to get the length of the actual car of the train.

Let the length of actual train's car be x.

And, the length of the car of model train = 5\ inches\ long.

<em>According to the scale of the model train, 1 inch is equivalent to 13.5 ft. </em>

<em>Thus, 5 inches is equivalent to </em>x.<em />

Now, to get the length of actual train's car using cross multiplication method:

\frac{1}{13.5} =\frac{5}{x}

By cross multiplying we get:

x=67.5\ feet.

Therefore, the length of the actual train's car is 67.5 feet.

7 0
3 years ago
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