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romanna [79]
3 years ago
13

Someone pls help me with this

Mathematics
1 answer:
Burka [1]3 years ago
6 0

the picture is blurry

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A square has an area of 49cm^2. What is the length of each side.
Vsevolod [243]

Answer:

7 cm

Step-by-step explanation:

The formula for finding the area of a square is A = a^2 (where a is the side length).

So let's substitute the given values in.

49 = a^2

a = sqrt(49)

a = 7 cm          <--- This is our answer

Hope this helps!

7 0
3 years ago
If you invest $10,000 at an annual rate of 7%, how much interest will you earn after one year?
AlladinOne [14]
10000 multiplied by 7/100(7%) multiplied by 1 (amount of years) =$700 interest
4 0
3 years ago
Please answer!! :) <br> I’ll make you brainiest!<br> Ty!
Sedaia [141]

Answer: number one is 10/5 and number 2 is  10/15

Step-by-step explanation:

5 0
3 years ago
Help!!!!! No weird answers pls
Papessa [141]

open the parenthes. and then after that you'll get 27+12x-15. if you simplify that then you'll get 12x+12

7 0
3 years ago
Read 2 more answers
Suppose that a company prints baseball cards. They claim that 30% of the cards feature rookies, 60% feature veterans, and 10% fe
liraira [26]

Answer:

H0: The distribution of players featured on the cards is 0.30 rookies, 0.60 veterans, and 0.10 All-Stars.

Ha: At least one of the proportions in the null hypothesis is false.

Step-by-step explanation:

On this case we need to apply a Chi squared goodness of fit test, and the correct system of hypothesis would be:

H0: The distribution of players featured on the cards is 0.30 rookies, 0.60 veterans, and 0.10 All-Stars.

Ha: At least one of the proportions in the null hypothesis is false.

And in order to test it we need to have observed and expected values. On this case we  can calculate the Expected values like this

E_{rookies}=50*0.3=15

E_{veterans}=50*0.6=30

E_{All stars}=50*0.1=5

The observed values are not provided. The statistic on this case is given by:

\chi^2 =\sum_{i=1}^n \frac{(O_i) -E_i}{E_i}

And this statistic follows a chi square distribution with k-1 degrees of freedom on this case k=3, since we have 3 groups.

We can calculate the p valu like this:

P(\chi^2 > \chi^2_{calculated})=p_v

And if the p value it's higher than the significance level we FAIL to reject the null hypothesis. In other case we reject the null hypothesis.

5 0
3 years ago
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