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Deffense [45]
3 years ago
10

Which expression is equivalent to 27 +4 •16

Mathematics
1 answer:
Pavel [41]3 years ago
6 0

Answer:

27+64

Step-by-step explanation:

lmk if you need an explanation

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I honestly don’t understand this at all can you help?
blondinia [14]
A. the first box is 7 
    the second box is 2
    the third box is 100 
    the fourth box is 6.5
    RULE: times 3 + 2
b. the first box is 45/2
    the second box is -0.75
    the third box is 0
    the fourth box is 2.75 
    RULE: times 5/2
c. the first box is 1 1/2
    the second box is 6
    the third box is -4
    the fourth box is -1.75
    RULE: times half add one
6 0
3 years ago
Read 2 more answers
-(1/2)³ is equivalent to?​
Brut [27]

Answer:

-0.125

Step-by-step explanation:

- Im learning about this , so im not really sure

5 0
3 years ago
I will mark you the brainiest for the correct answer, please be correct, Have a good day and take care, thanks. ( VIEW THE IMAGE
makkiz [27]

Mistake in Line 2 : Was in the determining the values for a ,b,c

Mistake in Line 4 : Not taking the square roots of both sides.

Step-by-step explanation:

{a}^{2}  +  {b}^{2}  =  {c}^{2}

First Mistake : Line 2

a = x \\ b = 6 \\ c = 10

Second Mistake : Line 4

136 =  {x}^{2}  \\ not \\ 136 = x

Correct Solution :

{x}^{2}  +  {6}^{2}  =  {10}^{2}  \\  {x}^{2}  =  {10}^{2}  -  {6}^{2}  \\  {x}^{2}  = 100 - 36 \\

{x}^{2}  = 64 \\  \sqrt{ {x}^{2} }  =  \sqrt{64}  \\ x = 6

3 0
3 years ago
Given two different circles O and Q, which of the following cases presents two circles with no (zero) common tangents?
borishaifa [10]
Concentric circles because if a line is tangent to one circle, it would only intersect teh other 
3 0
3 years ago
Read 2 more answers
A^2(64a^2-3)/3=27-4a^2/4
frutty [35]
The answer is a = 3/4 = 0.75

First get rid of the paranthesis,
{a}^{2} (64 {a}^{2}  - 3) = 64 {a}^{4} -  3 {a}^{2}
Then set the denominators equal:
\frac{ 256 {a}^{4}  - 12 {a}^{2}}{12}  =  \frac{81 - 12 {a}^{2} }{12}
Then remove the denominators and solve:
256 {a}^{4}  - 12 {a}^{2}  = 81 - 12 {a}^{2}
Eliminate -12a^2 by adding 12a^2 to both sides:
256 {a}^{4}  = 81
Take the fourth root of them or take the square root twice:
\sqrt[4]{256 {a}^{4} }  =  \sqrt[4]{81}   \\  4a = 3
Divide both sides by 4:
a =  \frac{3}{4}  = 0.75
7 0
3 years ago
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