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Vera_Pavlovna [14]
3 years ago
14

Given a scanner reference variable named input that has been associated with an input source consisting of a sequence of strings

and two int variables, count and longest, write the code necessary to examine all the strings in the input source and determine how long the longest string (or strings are). that value should be assigned to longest; the number of strings that are of that length should be assigned to count.
Computers and Technology
2 answers:
Makovka662 [10]3 years ago
7 0

The code that examines all the strings in the input source and determines how long the longest string (or strings are) is the following:

total = 0; % initial value is zero, in every while loop it will be incremented

while(input.hasNextInt()){

total += input.nextInt( );

}

BlackZzzverrR [31]3 years ago
5 0

Answer:

int count = 0;  //int variables

int longest =0;  // int variables

Scanner input = new Scanner(System.in); // given input is reference variable

String str= new String();  // creating object of sting class

while (input.hasNext()) // taking the input by using scanner reference

{

str= input.next();  // taking input in string

if (str.length() == longest) // checking condition

++count;  // increment the count

else

if (Str.length() > longest) // if string is greater then longest

{

longest = str.length(); // calculating length

count = 1;  // assign count to 1

}

}

Explanation:

Following are the description of the code :

  • Declared a two variable count and longest of  int type.
  • Create a object of String class i.e 'str".
  • Taking input in the string by using scanner reference i.e "input".
  • Finally checking the condition of if and else block and calculating the length of string and assign into longest variable.
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7 0
3 years ago
Write a program that generates 1,000 random integers between 0 and 9 and displays the count for each number. (Hint: Use a list o
masya89 [10]

Answer:

import random

count0, count1, count2, count3,

count4, count5, count6, count7,

count8, count9, i = [0 for _ in range(11)]

while i < 1000:

   number = random.randint(0,9)

   if number == 0:

       count0 = count0 + 1

   if number == 1:

       count1 = count1 + 1

   if number == 2:

       count2 = count2 + 1

   if number == 3:

       count3 = count3 + 1

   if number == 4:

       count4 = count4 + 1

   if number == 0:

       count5 = count5 + 1

   if number == 6:

       count6 = count6 + 1

   if number == 7:

       count7 = count7 + 1

   if number == 0:

       count8 = count8 + 1

   if number == 9:

       count9 = count9 + 1

   

   i = i+1

print("0's: "+ str(count0) + "\n"+ "1's: "+ str(count1) + "\n"+

"2's: "+ str(count2) + "\n"+ "3's: "+ str(count3) + "\n"+

"4's: "+ str(count4) + "\n"+ "5's: "+ str(count5) + "\n"+

"6's: "+ str(count6) + "\n"+ "7's: "+ str(count7) + "\n"+

"8's: "+ str(count8) + "\n"+ "9's: "+ str(count9) + "\n")

Explanation:

- Initialize variables to hold the count for each number

- Initialize <em>i</em> to control the while loop

- Inside the while loop, check for the numbers and increment the count values when matched.

- Print the result

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3 years ago
4.3 mini programs AP computer science
allochka39001 [22]

1.

name = input("Enter your name: ")

num1 = int(input("Hello "+name+ ", enter an integer: "))

num2 = int(input(name+", enter another integer: "))

try:

   if num1 % num2 == 0:

       print("The first number is divisible by the second number")

   else:

       print("The first number is not divisible by the second number")

except ZeroDivisionError:

   print("The first number is not divisible by the second number")

try:

   if num2 % num1 == 0:

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   else:

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except ZeroDivisionError:

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2.

import random, math

num1 = float(input("Enter a small decimal number: "))

num2 = float(input("Enter a large decimal number: "))

r = round(random.uniform(num1, num2), 2)

print("The volume of a sphere with radius " + str(r) + " is " + str(round(((4 / 3) * math.pi * (r ** 3)), 2)))

I hope this helps!

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