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2 years ago

Find the area of the figure. PLEASSEEEEEEEE!!!!!!!!

Mathematics

1 answer:

allochka39001 [22]2 years ago

5 0

Given:

side length = 6 ft

To find:

The area of the figure

Solution:

Area of the square = side × side

= 6 × 6

Area of the square = 36 ft²

Diameter of the semi-circle = 6 ft

Radius of the semi-circle = 6 ÷ 2 = 3 ft

Area of the semi-circle = $\frac{1}{2} \pi r^2$

$$=\frac{1}{2} \times 3.14 \times 3^2$

Area of the semi-circle = 14.13 ft²

Area of the figure = Area of the square - Area of the semi-circle

= 36 ft² - 14.13 ft²

= 21.87 ft²

Area of the figure = 21.9 ft²

The area of the figure is 21.9 ft².

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You have two coupons, one is for $25 off and the other is for 25% off. When would you use the $25 off coupon? When would you use

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3 years ago

The sum of the angles in a hexagon is 720°.

qwelly [4]

Given:

The sum of the angles in a hexagon is 720°.

$m\angle A=90^\circ,m\angle B=126.87^\circ,m\angle C=(3x)^\circ,m\angle D=90^\circ, m\angle E=143.13^\circ, m\angle F=143.13^\circ.$

To find:

(a) Equation to solve the value of x.

(b) The value of x.

Solution:

(a)

We have,

$m\angle A=90^\circ,m\angle B=126.87^\circ,m\angle C=(3x)^\circ,m\angle D=90^\circ, m\angle E=143.13^\circ, m\angle F=143.13^\circ.$

The sum of the angles in a hexagon is 720°.

$m\angle A+m\angle B+m\angle C+m\angle D+m\angle E+m\angle F =270^\circ$

$90^\circ+126.87^\circ+(3x)^\circ+90^\circ+143.13^\circ+143.13^\circ =270^\circ$

$90+126.87+(3x)+90+143.13+143.13 =720$

Therefore, the required equation is $90+126.87+(3x)+90+143.13+143.13 =720$ .

(b)

On solving the above equation, we get

$593.13+3x =720$

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$3x =126.87$

Divide both sides by 3.

$x =\dfrac{126.87}{3}$

$x =42.29$

Therefore, the value of x is 42.29.

(c)

We need to find the measure of angle C.

$m\angle C=(3x)^\circ$

$m\angle C=(3\times 42.29)^\circ$

$m\angle C=126.87^\circ$

Therefore, the measure of angle C is 126.87 degrees.

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3 years ago

How do I solve this problem

ziro4ka [17]

You have 3*6=18ft of straight line. then you have the circumference of a circle with a radius of 3 which is 9p

So the perimeter is 18+9p=46.27 ft (to the nearest hundredth)

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2 years ago