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natita [175]
3 years ago
8

Find the area of the figure. PLEASSEEEEEEEE!!!!!!!!

Mathematics
1 answer:
allochka39001 [22]3 years ago
5 0

Given:

side length = 6 ft

To find:

The area of the figure

Solution:

Area of the square = side × side

                               = 6 × 6

Area of the square = 36 ft²

Diameter of the semi-circle = 6 ft

Radius of the semi-circle = 6 ÷ 2 = 3 ft

Area of the semi-circle = \frac{1}{2} \pi r^2

                                      $=\frac{1}{2} \times 3.14 \times 3^2

Area of the semi-circle = 14.13 ft²

Area of the figure = Area of the square - Area of the semi-circle

                              = 36 ft² - 14.13 ft²

                              = 21.87 ft²

Area of the figure = 21.9 ft²

The area of the figure is 21.9 ft².

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A student sets up two reactions. Reaction 1 uses 0.180 mol/L of reactant, and Reaction 2 uses 0.510 mol/L of reactant. How many
il63 [147K]

Given the data from the question, reaction 2 is 2.83 times faster compared to reaction 1

<h3>Data obtained from the question</h3>
  • Molarity of reaction 1 (R₁) = 0.180 mol/L
  • Molarity of reaction 2 (R₂) = 0.510 mol/L
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<h3>How to determine the comparison of reaction 2 to reaction 1</h3>

We can determine how many times faster is reaction 2 to reaction by doing the following:

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R₂ / R₁ = 2.83

Cross multiply

R₂ = 2.83 × R₁

From the above illustration, we can see that reaction 2 is 2.83 times faster than reaction 1

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4 0
1 year ago
The perimeter of a quarter circle is 14.28 KM. What is the quarter circle's radius?
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14.28km= 2(3.14)r
14.28= 6.2831853072r
divide both sides by 6.2831853072
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ANSWER: The radius is 2.27km

Hope this helps! :)
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That about sums it all up!

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